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aleksandr82 [10.1K]
3 years ago
6

A car traveling comes to a stop at a red light.How many forces are taking place?

Physics
1 answer:
charle [14.2K]3 years ago
6 0

i think it depends on the speed rate

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How fast would the International Space Station (ISS) have to travel to maintain a circular orbit a distance of 1400 km above the
professor190 [17]

Answer:

The International Space Station move at 7.22 km/s.

Explanation:

Orbital speed of satellite is given by  v=\sqrt{\frac{GM}{r}}, where G is gravitational constant, M is mass of Earth and r is the distance to satellite from centre of Earth.

r = R + h = 6350 + 1400 = 7750 km = 7.75 x 10⁶ m

G = 6.673 x 10⁻¹¹ Nm²/kg²

M = 5.98 x 10²⁴ kg

Substituting

              v=\sqrt{\frac{6.673\times 10^{-11}\times 5.98\times 10^{24}}{7.75\times 10^6}}=7223.86m/s=7.22km/s

  The International Space Station move at 7.22 km/s.      

4 0
3 years ago
The table below shows a sample wavelength of each type of electromagnetic radiation, along with its frequency and energy.
trasher [3.6K]

Answer:

D lower energy waves is most likely the safest if one is exposed to.

5 0
3 years ago
How to find acceleration?
Yanka [14]
Acceleration = Change in Velocity / time
 
                a  =  (v - u) / t

Where v = final velocity in m/s              
            u = initial velocity in m/s 
            t = time in seconds.
            a = acceleration in m/s²

A proper record of the changes in velocity with the corresponding time would help find the acceleration.  
4 0
3 years ago
Read 2 more answers
Which would you expect to freeze faster pure water or salt solution why?
krek1111 [17]
Pure water.

A salt solution contains impurities whereas pure water will not contain any impurities.

Impurities increase the boiling point (freezing point) of a substance.

Thus, I would expect the pure water solution to freeze faster than the salt solution.
6 0
3 years ago
An electron passes through a point 2.83 cm 2.83 cm from a long straight wire as it moves at 35.5 % 35.5% of the speed of light p
igor_vitrenko [27]

Answer:

The magnitude of electron acceleration is 2.34 \times 10^{15} \frac{m}{s^{2} }

Explanation:

Given:

Distance from the wire to the field point r = 2.83 \times 10^{-2} m

Speed of electron v = 35.5 \%c

Current I = 17.7 A

For finding the acceleration,

First find the magnetic field due to wire,

  B = \frac{\mu _{o}I }{2\pi r }

Where \mu_{o} = 4\pi   \times 10^{-7}

  B = \frac{4\pi \times 10^{-7}  \times 17.7 }{2\pi (2.83 \times 10^{-2} ) }

  B = 12.50 \times 10^{-5} T

The magnetic force exerted on the electron passing through straight wire,

  F = qvB  

  F = 1.6 \times 10^{-19} \times 0.355 \times 3 \times 10^{8} \times 12.50 \times 10^{-5}

  F = 21.3 \times 10^{-16} N

From the newton's second law

  F = ma

Where m = mass of electron = 9.1 \times 10^{-31} kg

So acceleration is given by,

   a = \frac{F}{m}

   a = \frac{21.3 \times 10^{-16} }{9.1 \times 10^{-31} }

   a = 2.34 \times 10^{15} \frac{m}{s^{2} }

Therefore, the magnitude of electron acceleration is 2.34 \times 10^{15} \frac{m}{s^{2} }

7 0
3 years ago
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