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serious [3.7K]
3 years ago
12

Could someone help me with this please?

Physics
2 answers:
ycow [4]3 years ago
6 0

Answer:

you could measure several properties of

the unknown liquid and compare them with the properties of known

substances. You might observe and measure such properties as color,

odor, texture, density, boiling point, and freezing point.

ratelena [41]3 years ago
6 0

Answer:

Compare the various physical properties of the substance.

Explanation:

One way is to compare the various physical properties of the substance. Let's take a look at those:

Identify the physical identity of each substance. That is, it the substance solid, or powder, or granulated (in small granules)

Next, the color of the substance will also help as a physical property. For example, is the substance bright, shiny, dull in color, etc.

Another property of the test can be the electrical conductance. For instance, does the substance conduct electricity or not.

Finally, test if the substance dissolves in a solvent, say water in this case. If it dissolves, it is likely to be a soluble salt. If not, then it is likely to be an insoluble salt.

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Answer:

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120 x 1,000 = 120,000.

This is the correct answer and formula.

Hope this helps!

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