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3 years ago

Adding a nonvolatile solute to a solution decreases the vapor pressure of the solution. True or False

Physics

1 answer:

Feliz [49]3 years ago

7 0

Answer:

True.

Explanation:

Adding a non - volatile solute to solvent, decreases the tendency for water molecules to evaporate into gas phase i.e these non - volatile solute particles obstruct or reduce the rate of evaporation. Few water molecules in the vapour.

Therefore, Adding a nonvolatile solute to a solution decreases the vapor pressure of the solution while

Vapor pressure is a measurement of the likelihood of the molecules of a pure solvent to change from the liquid to the vapor phase.

Using Raoult's Law:

Psol = Xsolv * P°solv

where:

Psol = the vapor pressure of the solvent above the solution,

Xsolv = the mole fraction of the solvent in the solution, and

P°solv = the vapor pressure of the pure solvent.

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What would a series circuit be used for?

igor_vitrenko [27]

Answer:

Explanation:

a series circuit would be an odd choice to power a battery or light a lamp when a direct would be much more efficient, and it's not converting types of energy, so C is the best possible answer

6 0

3 years ago

When a mass rests on a surface, the surface "pushes up" on the object with a force that is equal in

Airida [17]

Answer: 294 N

Explanation:

Since the Normal Force $N$ is equal to the weight $W$ of the dog, we have:

$N=W=m.g$

Where:

$m=30 kg$ is the mass of the dog

$g=9.8 m/s^{2}$ is the acceleration due to gravity on the Earth's surface

Solving:

$N=W=(30 kg)(9.8 m/s^{2})$

$N=294 N$

8 0

3 years ago

A 3 kg object is moving along a horizontal surface. The kinetic energy of the object is increasing at a constant rate of 6 J/m;

Whitepunk [10]

To solve this problem we will apply the concepts of energy conservation and Newton's second law that defines force as the product of the object's mass with its acceleration. Additionally we will apply concepts related to the kinematics equations of linear motion.

For conservation of energy we have that work is equal to kinetic energy therefore,

$W = KE$

$Fd = \frac{1}{2} mv^2$

Here,

F = Force

d = Displacement

m = Mass

v= Velocity

At the same time we have the relation of

$F = \frac{W}{d}$

Therefore the value of the force can be interpreted as the rate of increase in energy per unit of distance, which makes it equivalent to

$F = \frac{W}{d} = 6J/m$

Applying Newton's Second Law

$F = ma$

$6J/m = (3kg)a$

$a = 2m/s^2$

In 4 seconds final velocity of the object becomes

$v = at$

$v= 2*4$

$v= 8m/s$

Then the work done is equal to,

$W = KE$

$W = \frac{1}{2} mv^2$

$W = \frac{1}{2} (3)(82)$

$W = 96J$

Then the displacement is,

$W = F*d$

$d = \frac{W}{F}$

$d = \frac{96}{6}$

$d = 16 m$

Therefore the distance moved is 16m

7 0

4 years ago

A long straight wire carries current to the right of the page. A rectangular loop is positioned directly under the wire in the p

slavikrds [6]

Answer:

Correct option A.

The net force exerted by this loop on the straight wire with the current is directed TOWARDS THE LOOP

Explanation:

The magnetic field exerts a force on a current-carrying wire in a direction given by the right-hand rule 1 (the same direction as that on the individual moving charges). This force can easily be large enough to move the wire since typical currents consist of very large numbers of moving charges.

Given that,

The wire's current is directed towards the right of the page.

The rectangular loops carry current in a clockwise direction.

Since the 'dot' field is increasing hence the induced magnetic field is 'cross', i.e. into the page and by the right-hand rule, the induced current is clockwise.

Then the magnetic field is into the page.

Since was known that

F= iL×B

Note the current is through the wire. Then, the length is in direction of the current.

Note: this equation gives the magnetic force that acts on a length L of a straight wire carrying a current (i) and immersed in a uniform magnetic field (B), that is perpendicular to the wire.

So, the magnetic field is always perpendicular to the current.

So using right hand rule,

F = i(L×B)

The length is to the right i.e. +x direction and the Magnetic field is perpendicular to the plane, i.e. in the +z direction

F = i (L•i × B•k)

F = iLB (i×k)

F = iLB•(-j)

F = -iLB•j

Then, the force is in the negative y-direction i.e. towards the loop.

8 0

4 years ago

Suppose you take two non-zero displacements represented by vectors A & B.The magnitude of A is 5 m and the magnitude of B is

olga55 [171]

Answer:

a. When the total displacement is -(A + B)

b. A + B = 1 m or -(A + B) = -11 m

c. 0 m

Explanation:

a. Under what circumstances can you end up back at your starting point?

If we have the displacement A and displacement B. The total displacement is A + B. We would end up at the starting point if we take a displacement -(A + B) from point B

b. What is the magnitude of the largest displacement you can end up from the starting point?

The maximum displacement we can obtain is when A and B are in the same direction. So A + B = 5 m + 6 m = 11 m or -A - B = -(A + B) = -11 m.

c. When A and B are perpendicular, what is the component of B in the direction of A?

Since A is perpendicular to B, the angle between A and B is 90°

So the component of B in A,s direction is Bcos90° = B × 0 = 0 m

8 0

4 years ago