x^2=4x-5
subtract 4x from both sides
x^2-4x=-5
add 5 to both sides
x^2-4x+5=0
input into quadratic formula which is x=
or
si ax^2+bx+c
so a=1
b=-4
c=5
input
=
=
=
![\frac{4+2 times \sqrt{-1} }{2}= \frac{6 times \sqrt{-1} }{2}=3 times \sqrt{-1} [\tex][\tex]\sqrt{-1}](https://tex.z-dn.net/?f=%20%5Cfrac%7B4%2B2%20times%20%20%5Csqrt%7B-1%7D%20%20%7D%7B2%7D%3D%20%20%5Cfrac%7B6%20times%20%20%5Csqrt%7B-1%7D%20%20%7D%7B2%7D%3D3%20times%20%20%5Csqrt%7B-1%7D%20%5B%5Ctex%5D%5B%5Ctex%5D%5Csqrt%7B-1%7D%20%20)
representeds by 'i' so solution is 3i
then if other way around then wyou would do
=
and [\tex]\sqrt{-1} [/tex] is represented by i
the solution is x=3i or i (i=
)
but i is not real, it is imaginary so there are no real solution so the answer is C
Answer:
∠ WZX = 50°
XW is not an altitude.
Step-by-step explanation:
16. See the attached figure.
XW is the angle bisector of ∠ YXZ, hence, ∠ WXY = ∠ WXZ
Now, given that ∠ YXZ = 8x + 34 and ∠ WXY = 10x - 13
Hence, ∠ YXZ = 2 ∠ WXY
⇒ 8x + 34 = 2(10x - 13)
⇒ 8x + 34 = 20x - 26
⇒ 12x = 60
⇒ x = 5.
Hence, ∠ XZY = ∠ WZX = 10x = 50° (Answer)
Now, ∠ WXZ = ∠ WXY = 10x - 13 = 37°
Hence, from Δ WXZ,
∠ WZX + ∠ WXZ + ∠ XWZ = 180°
⇒ 50° + 37° + ∠ XWZ = 180°
⇒ ∠ XWZ = 93° ≠ 90°
Hence, XW is not an altitude. (Answer)
This result is actually true for any exterior angle. The exterior angle of a triangle is equal to the sum of the two remote angles, and above is a short proof of it.
Option B - y=-3(x+3)^2+6
Step-by-step explanation:
Step 1:
The equation of any parabola in the standard form with vertex at the origin is y^2 = 4ax . When it opens upward, the equation would be x^2 = 4ay
When the vertex is shifted to a point other than the origin, the equation would be
(x-h)^2 = 4a(y-k)
Step 2 :
Given that the vertex of the parabola is at (-3, 6). We will have the x and y co-ordinate shifted with this value.
So the equation of the parabola will have x and y shifted to x-(-3)) and y-6
=> x+3 and y-6
Step 3:
Based on the above 2, we can see that option B y=-3(x+3)^2+6 could be the equation of the parabola.
5 is adding and 6 is subtracting
