Quarantine 1
Hope this helps! If you have questions, let me know! :)
First, we calculate the lengths of each line using the
distance formula.
AB = (3 - -5) = 8
CA = (1 - -5) = 6
CB can be calculated using the hypotenuse equation:
CB = sqrt (AB^2 + CA^2)
CB = sqrt (8^2 + 6^2)
CB = 10
The perimeter is therefore:
perimeter = AB + CA + CB = 8 + 6 + 10
perimeter = 24 units
Abswer:
C. 24 units
Given the relationship T^2 = A^3, to compare the values of the orbital periods of X and Y, it would be easier to assign values. Since the Planet Y's distance A is twice that of Planet X's distance A, this can be shown below:
For Planet X (where A = 2):
T^2 = 2^3
T = 2.828
For Planet Y (where A = 4)
T^2 = 4^3
T = 8
Therefore, planet Y's orbital period is larger by (8/2.828) = 2.83 times.
Answer:
Step-by-step explanation:
A is a 2 x 2 coefficient matrix with repeated eigenvalues
The linear equation is given by the relationship y' = Ay
...............(1)
................(2)
Vertical tangents on the line,
,
,
...........(2)
Substitute these values into equation (2)
Answer:
False
Step-by-step explanation:
70 is larger than 58 to be a factor and that makes the point that this is false.