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3 years ago

The perimeter of a rectangle is 63cm.The length of its shorter side is 9cm.Find its area

Mathematics

2 answers:

kodGreya [7K]3 years ago

5 0

Answer:

202.5cm^2

Step-by-step explanation:

P=2l+2w

63=2(9)+2w

63=18+2w

63-18=2w

45=2w

divide both sides by 2

22.5=w

check:

P=2(9)+2(22.5)

=18+45

=63

Area=l×w

=22.5×9

=202.5cm²

DENIUS [597]3 years ago

3 0

Answer:

A = 202.5 cm²

Step-by-step explanation:

P = 63 = 2×9 + 2w

2w = 63 - 18

2w = 45

w = 22.5 cm

A = w×l = 9×22.5 = 202.5 cm²

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2 years ago

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valina [46]

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Step-by-step explanation:

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3 years ago

Read 2 more answers

3. Find the missing side lengths. Leave your answers as radicals in simplest form. Show your work to support

7nadin3 [17]

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Step-by-step explanation:

Since this is a 45-45-90 triangle we know that side b is equal to $b=2\sqrt{2}$ .

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Keith_Richards [23]

The answer would be 74,000. hope this helps
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