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Dennis_Churaev [7]
3 years ago
12

a fixed amount of ideal gas is held in a rigid container that expands negligibly when heated. at 20 the gas pressure is p. if we

added enough heat to increase the temperature from 20 to 40, the pressure will be
Physics
1 answer:
pantera1 [17]3 years ago
5 0

Answer:

When the temperature of the gas is increased from 20 to 40, the pressure will be 2p

Explanation:

Given;

initial temperature of the gas, T₁ = 20 K

final temperature of the gas, T₂ = 40 k

initial pressure of the gas, P₁ = P

final pressure of the gas, P₂ = ?

Apply pressure law of gases;

\frac{P_1}{T_1} = \frac{P_2}{T_2} \\\\P_2 = \frac{P_1T_2}{T_1} \\\\P_2 = \frac{40P}{20} \\\\P_2 = 2P

Therefore, when the temperature of the gas is increased from 20 to 40, the pressure will be 2p

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A pair of slits in a double slit experiment are illuminated with monochromatic light of wavelength 480 nm. The slits are separat
Romashka-Z-Leto [24]

Using the appropriate approximations:

dx/L = mλ

d = slit separation

x = fringe spacing

L = distance between slits and screen

m = some integer, used to determine the distance from the central bright fringe to another bright fringe


We don't really need a value for m because we're calculating the distance between any pair of consecutive fringes. Let's just set m = 1


Given values:

d = 1.0mm

L = 2.0m

λ = 480nm


Substitute the terms in the equation with our given values and solve for x:

1.0*10⁻³*x/2 = 480*10⁻9

<h3>x = 0.96mm</h3>
8 0
3 years ago
A 15kg boulder is moved from the Earth to the Moon. Explain what happens to the mass and weight of the boulder.​
elena-14-01-66 [18.8K]

Answer:

The mass of the boulder remains constant, while its weight decreases with respect to the value of gravitational force on the moon.

Explanation:

The mass of the boulder = 15 kg

On the earth, its mass remains 15 kg. But its weight is;

weight = m x g

           = 15 x 9.8

           = 147 N

The boulder's weight on the earth is 147 N.

When transferred to the moon, the mass remains constant i.e 15 kg. But its weight decreases due to a change in the value of acceleration due to gravity on the moon. Thus, the boulder becomes lighter in weight.

6 0
3 years ago
Anthony is standing on the top of a building 10 m high holding a 7 kg
shepuryov [24]

Answer:

548.8 J

Explanation:

5 0
3 years ago
An overnight rainstorm has caused a major roadblock. Three massive rocks of mass m1=528 kg, m2=838 kg and m3=311 kg have blocked
JulsSmile [24]

Answer:

FA=419,25N

F12=287,25N

Explanation:

The bulldozer is moving the rocks as one system, the weigth for the complete system is:

M=m1+m2+m3=1677kg

From newton´s second law the acceleration can be related to the force by:

FA=m*a=1677kg*0,250m/s^{2}=419,25N

on the middle rock we have the force F12 from the first to the middle rock on the direction of movement and F32 from the las rock to the middle rock on the opposite direction of movement.

For the last rock to accelerate at the same rate it must be subjected to a force:

F23=m3*a=311kg*0,250m/s^{2} =77,75N

This equals the force F32 on the opposite direction. the resultant force on the middle rock to mantain this acceleration should be:

F2=m2*a=838kg*0,250m/s^{2} =209,5N

The sum of all the forces applied to the middle rock is:

F2=F12-F32

Solving for F12:

F12=F2+F32=209,5N+77,75N=287,25N

3 0
3 years ago
What is the current in a circuit if 3.50 C of charge passes any given point in a circuit in 1.80 s?
stepan [7]

Answer:

I = 1.944 A

Explanation:

<u>Given the following data;</u>

Charge, Q = 3.5C

Time, t = 1.8 secs

Charge of a substance is given by the formula;

Q = It

Where;

Q is the amount of charge measured in Colombs.

I is the current measured in Amperes.

t is the time measured in seconds.

Making I the subject of formula, we have

I = \frac {Q}{t}

I = \frac {3.5}{1.8}

I = 1.944 A

Therefore, the current in the circuit is 1.944 Amperes.

7 0
3 years ago
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