Using the appropriate approximations:
dx/L = mλ
d = slit separation
x = fringe spacing
L = distance between slits and screen
m = some integer, used to determine the distance from the central bright fringe to another bright fringe
We don't really need a value for m because we're calculating the distance between any pair of consecutive fringes. Let's just set m = 1
Given values:
d = 1.0mm
L = 2.0m
λ = 480nm
Substitute the terms in the equation with our given values and solve for x:
1.0*10⁻³*x/2 = 480*10⁻9
<h3>x = 0.96mm</h3>
Answer:
The mass of the boulder remains constant, while its weight decreases with respect to the value of gravitational force on the moon.
Explanation:
The mass of the boulder = 15 kg
On the earth, its mass remains 15 kg. But its weight is;
weight = m x g
= 15 x 9.8
= 147 N
The boulder's weight on the earth is 147 N.
When transferred to the moon, the mass remains constant i.e 15 kg. But its weight decreases due to a change in the value of acceleration due to gravity on the moon. Thus, the boulder becomes lighter in weight.
Answer:


Explanation:
The bulldozer is moving the rocks as one system, the weigth for the complete system is:

From newton´s second law the acceleration can be related to the force by:

on the middle rock we have the force F12 from the first to the middle rock on the direction of movement and F32 from the las rock to the middle rock on the opposite direction of movement.
For the last rock to accelerate at the same rate it must be subjected to a force:

This equals the force F32 on the opposite direction. the resultant force on the middle rock to mantain this acceleration should be:

The sum of all the forces applied to the middle rock is:

Solving for F12:

Answer:
I = 1.944 A
Explanation:
<u>Given the following data;</u>
Charge, Q = 3.5C
Time, t = 1.8 secs
Charge of a substance is given by the formula;
Where;
Q is the amount of charge measured in Colombs.
I is the current measured in Amperes.
t is the time measured in seconds.
Making I the subject of formula, we have
I = 1.944 A
Therefore, the current in the circuit is 1.944 Amperes.