A single light beam is split into two equal beams, denoted a and b. beam a travels through a medium with a higher index of refra
ction than the medium that beam b travel through. when both beams exit their media back into air, how do their wavelengths compare
1 answer:
Answer:
c) Both beams have the same wavelength.
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I believe strength and direction
Answer:
The answer is wavelength
Answer:
+14.0 m/s
Explanation:
we have mV + Mv = mU + Mu we solve for U = (mV + Mv - Mu)/m = (328*19.1 + 790*13 - 790*15.1)/328 = 14. Answer
2^4/2^7 = 16/128 = 0.125
(1/2)^3= 0.125
1/8= 0.125
a and f are equivalent
