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yan [13]
3 years ago
13

A single light beam is split into two equal beams, denoted a and b. beam a travels through a medium with a higher index of refra

ction than the medium that beam b travel through. when both beams exit their media back into air, how do their wavelengths compare
Physics
1 answer:
nevsk [136]3 years ago
4 0

Answer:

c) Both beams have the same wavelength.

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If a substance can not be separated physically or chemical it is an element.

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An object has a mass of 20kg, what is its weight on Earth?
umka2103 [35]

Answer:

The formula is W=mg.

W=20×10=200.

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Which of the following steps to solve a problem is completed last?
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A 100 kg mass is pulled along a frictionless surface by a horizontal force F such that its acceleration is 8.0 m/s2. A 20 kg mas
nadya68 [22]

Answer:

a) 60 N

b) 860 N

Explanation:

Given that,

m_1 = 100 kg

m_2 = 20 kg

a_{1} = 8.0 \frac{m}{s^{2}}

a_{2} = 3.0 \frac{m}{s^{2}}

a) By Newton's Law,

∑F_{m_2,x} = f_k = m_{2} * a_{2}

∑F_{m_2,y} = F_{N} - m_{2} * g = 0

Hence,

f_k = m_2 * a_2 = 20 * 3 = 60 N

b) By Newton's Law

∑F_{m_1,x} = F = m_{1} * a_{1}

Hence,

F = m_{1} * a_{1} = 100 * 8 = 800 N

Net force acting on 100 kg mass,

F_{net} = F + f_k = 800 + 60 = 860 N

6 0
3 years ago
In the photoelectric effect, it is found that incident photons with energy 5.00ev will produce electrons with a maximum kinetic
Yakvenalex [24]
From Literature:

The amount of energy in the photons is given by this equation:

E = hf

where E = energy
            h = Planck's constant = 6.63 * 10^-34 Joule seconds
            f = frequency of the light, Hz

Given:

E= 3.00 eV and Planck's constant 

To solve for the frequency, E = 3.00 eV

1 electronvolt = 1.60218 x 10^-19 Joules

3 * 1.60218 x 10^-19 Joules = 6.63 * 10^-34 Joule seconds * f 
f = 7.25 x 10^14 /second or hertz

Therefore, the threshold frequency of the material is 7.25 x 10^14 Hertz.


7 0
4 years ago
Read 2 more answers
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