Answer:
P₁ = 219.3 Pa
Explanation:
This fluid mechanics problem, we can use that the pressure is distributed with the same value throughout the system, which is Pascal's principle.
Let's use the subinidce1 for the small diameter and the subscript 2 for the larger diameter.
P₁ = P₂
pressure is defined by
P = F / A
we subtitute
F₁ / A₁ = F₂ / A₂
F₁ = F₂ A₁ / A₂
the area in a circle is
A = π r² = π d² / 4
we substitute
F₁ = F₂ (d₁ / d₂)²
we calculate
F₁ = 17640 (2/32)²
F₁ = 68.9 N
Having the force to be applied we can find the air pressure on the small plunger
P₁ = F₁ / A₁
P₁ = F₁ 4 / π d₁²
let's calculate
P₁ = 68.9 4 / (π 0.02²)
P₁ = 219.3 Pa
F=ma so a=F/m
ax=180/270=0.67m/s^2
ay=390/270=1.44m/s^2
Magnitude = sqrt((0.67^2)+(1.44^2))=1.59m/s^2
Direction- Tan(x)=0.67/1.44=0.47 Tan^-1(x)=25 degrees
Answer:
<h3>a) </h3><h3>
<u>Question</u><u>:</u><u>-</u></h3>
- Rubber is a good conductor of electricity.
<h3>
<u>A</u><u>n</u><u>s</u><u>w</u><u>e</u><u>r</u><u>:</u><u>-</u></h3>
- <em>I</em><em>t</em><em>'</em><em>s</em><em> </em><em>i</em><em>n</em><em>c</em><em>o</em><em>r</em><em>r</em><em>e</em><em>c</em><em>t</em><em> </em><em>s</em><em>e</em><em>n</em><em>t</em><em>e</em><em>n</em><em>c</em><em>e</em><em>.</em>
- As we know that, rubber are an insulators of electricity, and they do not not have free ions which can help in conducting electricity.
<u>S</u><u>o</u><u> </u><u>c</u><u>o</u><u>r</u><u>r</u><u>e</u><u>c</u><u>t</u><u> </u><u>s</u><u>e</u><u>n</u><u>t</u><u>e</u><u>n</u><u>c</u><u>e</u><u> </u><u>i</u><u>s</u><u>:</u>
- <em>R</em><em>u</em><em>b</em><em>b</em><em>e</em><em>r</em><em> </em><em>i</em><em>s</em><em> </em><em>a</em><em> </em><em>b</em><em>a</em><em>d</em><em> </em><em>c</em><em>o</em><em>n</em><em>d</em><em>u</em><em>c</em><em>t</em><em>o</em><em>r</em><em> </em><em>o</em><em>f</em><em> </em><em>e</em><em>l</em><em>e</em><em>c</em><em>t</em><em>r</em><em>i</em><em>c</em><em>i</em><em>t</em><em>y</em><em>.</em>
<h3>b)</h3><h3>
<u>Q</u><u>u</u><u>e</u><u>s</u><u>t</u><u>i</u><u>o</u><u>n</u><u>:</u><u>-</u></h3>
- Electroplating wastes are useful to human health and environment.
<h3>
<u>Answer</u><u>:</u><u>-</u></h3>
- <em>It's</em><em> </em><em>incorrect</em><em> </em><em>sentence</em><em>.</em><em> </em>
- As we know that, electroplating of substances releases harmful and toxic substances into the environment causing serious health issues in human, so it's waste substances released into environment can have very harmful effects.
<u>So correct sentence is:</u>
- <em>Electroplating wastes are </em><em>harmful</em><em> </em><em>to human health and </em><em>environment</em><em>.</em>
<h3>
c)</h3><h3>
<u>Question</u><u>:</u><u>-</u></h3>
- In an LED bulb, the shorter lead is connected to the positive terminal of the battery.
<h3>
<u>Answer</u><u>:</u><u>-</u></h3>
- <em>It's incorrect sentence. </em>
- As we know that, in an LED bulb their are two terminals that is the positive and the negative. So here the lead connected to the positive terminal is always slightly longer than the lead connected to negative terminal of the bulb.
<u>So correct sentence is:</u>
- <em>In an LED bulb, the </em><em>longer</em><em> lead </em><em>i</em><em>s</em><em> </em><em>connected to the positive terminal of the battery.</em>
<h3>
d)</h3><h3>
<u>Question</u><u>:</u><u>-</u></h3>
- Pure water conducts electricity.
<h3>
<u>Answer</u><u>:</u><u>-</u></h3>
- <em>It's incorrect sentence. </em>
- As we know that, pure water is a form of H2O where Hydrogen (H) is positive ion and Oxygen (O) is a negative ion which can conduct electricity when they are in individuals but as in pure water they are in combined form of compound H2O in which they become neutral and can't conduct any electricity.
<u>So correct sentence is:</u>
- <em>P</em><em>ure water </em><em>c</em><em>a</em><em>n</em><em>'</em><em>t</em><em> </em><em>conduct</em><em> </em><em>electricity.</em>
Explanation:
Mass of the ball, m = 0.058 kg
Initial speed of the ball, u = 11 m/s
Final speed of the ball, v = -11 m/s (negative as it rebounds)
Time, t = 2.1 s
(a) Let F is the average force exerted on the wall. It is given by :


F = 0.607 N
(b) Area of wall, 
Let P is the average pressure on that area. It is given by :


P = 0.202 Pa
Hence, this is the required solution.