Find the lowest terms fraction that's equal to 0.33.

Mathematics

2 answers:

irinina [24]3 years ago

5 0

The answer is 33/100

Len [333]3 years ago

3 0

33/100

Step-by-step explanation:

we turned the number into a fraction

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What is the solution to the equation below? 2(x - 3) = 2x 5?

Westkost [7]

2 ( x - 3) = 2x 5
2x - 6 = 10x
2x - 10x = 6
-8x = 6
x = -6/8
x = -3/4

So, final answer is -3/4

Hope it helped

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4 years ago

In 7 days, a group of workers can plant 56 acres. What is their rate in acres per day?

tamaranim1 [39]

Answer:

Step-by-step explanation:

56/7=8

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4 years ago

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The table gives the probability distribution of the number of DVDs sold per day at a music store. What is the probability of 5 o

MrMuchimi

Answer:

C. 0.8125

Step-by-step explanation:

The probability to sell 5 or more DVDs in a day is the complement of the probability of selling less than 5 DVDs in a day, since sales <5 DVDs + sales >= 5 DVDs = 100% of the sales.

So, we know what's the probability of selling less than 5 DVDs in a day is... it's 0.1875

So, to find the possibility of selling 5 or more DVDs in a day, we take 100% of the chances (1.0) and we subtract the probability of selling <5 DVDs in a day:

P = 1.0 - 0.1875 = 0.8125

C. 0.8125 is your answer.

8 0

4 years ago

A tank contains 30 lb of salt dissolved in 500 gallons of water. A brine solution is pumped into the tank at a rate of 5 gal/min

Dmitry [639]

At any time $t$ (min), the volume of solution in the tank is

$500\,\mathrm{gal}+\left(5\dfrac{\rm gal}{\rm min}-5\dfrac{\rm gal}{\rm min}\right)t=500\,\mathrm{gal}$

If $A(t)$ is the amount of salt in the tank at any time $t$ , then the solution has a concentration of $\dfrac{A(t)}{500}\dfrac{\rm lb}{\rm gal}$ .

The net rate of change of the amount of salt in the solution, $A'(t)$ , is the difference between the amount flowing in and the amount getting pumped out:

$A'(t)=\left(5\dfrac{\rm gal}{\rm min}\right)\left(\left(2+\sin\dfrac t4\right)\dfrac{\rm lb}{\rm gal}\right)-\left(5\dfrac{\rm gal}{\rm min}\right)\left(\dfrac{A(t)}{50}\dfrac{\rm lb}{\rm gal}\right)$