Do Brain cells act and look like skin cells? Why or why not?

A rock is thrown down from the top of a cliff with a velocity of 3.61 m/s (down). The cliff is 28.4 m above the ground. Determin

Katarina [22]

I’m not sure look it up in the internet!

4 0

2 years ago

Carbon burns with oxygen to produce carbon dioxide gas. which of these shows the correct chemical reaction?

Ksju [112]

B

Chemical equations always have an arrow

4 0

3 years ago

Read 2 more answers

The engine in an imaginary sports car can provide constant power to the wheels over a range of speeds from 0 to 70 miles per hou

Inessa05 [86]

Answer:

a) 4.40 s

b) 2.20 s

Explanation:

Given parameters are:

At constant power ,

initial speed of the car, $v_0=0$

final speed of the car, $v=32$ mph

At full power,

initial speed of the car, $v_0=0$

final speed of the car, $v=64$ mph

a)

At constant power, $KE = \frac{1}{2} mv^2$

At full power, $KE = \frac{1}{2} m(2v)^2$

So $KE_f = 4KE_i$

So, time to reach 64 mph speed is 4 times more than the initial time

$t = 4*1.10 =4.40$ s

b)

$v=v_0+at\\a=\frac{v-v_0}{t}=\frac{32-0}{1.1/3600}=104727.27$ $miles/hours^2$

For final 64 mph speed,

$v=v_0+at\\t=\frac{v-v_0}{a}=\frac{64-0}{104727.27} = 6.111*10^{-4}$ $hours$ = $6.111*10^{-4}*3600=2.20$ s

7 0

2 years ago

You want to estimate the height of the Empire State Building. You start at its base and walk 15 m away. Then you approximate the

MatroZZZ [7]

Answer:

429 m

Explanation:

In this exercise you are suppose to simulate a right triangle, the catheti are the distance you walked and the height of the empire state building.

tan(88) = (height) /(distance you walked)

28.64 = height / 15

height = 429 m

8 0

2 years ago

A 500 kg object is hanging from a spring attached to the ceiling. If the spring constant in the spring is 900 N/kg, how far does

My name is Ann [436]

We are given that a 500 kg object is hanging from a spring. To determine the amount the spring is stretched we will use Hook's law, which states the following:

$F=kx$

Where:

$\begin{gathered} F=\text{ force} \\ k=\text{ spring constant} \\ x=\text{ distance stretched} \end{gathered}$

Since the object is hanging the only force acting on the spring is the weight of the object. The weight of the object is:

$F_g=mg$

Where:

$\begin{gathered} m=\text{ mass} \\ g=\text{ acceleration of gravity} \end{gathered}$

Plugging in the values we get:

$F_g=(500\operatorname{kg})(9.8\frac{m}{s^2})$

Solving the operations:

$F_g=4900N$

Now we solve for "x" from Hook's law by dividing both sides by "k":

$\frac{F}{k}=x$

Now we plug in the known values:

$\frac{4900N}{900\frac{N}{m}}=x$

Solving the operations:

$5.4m=x$

Therefore, the spring is stretched by 5.4 meters.

7 0

7 months ago