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Stels [109]
4 years ago
9

Hahah I look pregnant don’t I

Physics
1 answer:
n200080 [17]4 years ago
8 0
I see a pillow

But you see...this bobcat
Cute ain’t it?

You might be interested in
a bicycle rider pedals towards a hill at a speed of 7.5w/s. the combined mass of the bicycle and the rider is 75.0kg the cycle a
siniylev [52]

Answer:

2.8125 meters

Explanation:

I will assume 7.5 m/s

When the Kinetic Energy is entirely converted to Potential energy the max height will have been reached

KE = PE

1/2 m v^2 = mgh     divide by m

1/2 v^2 = gh         looking for  h     so divide both sides by

1/2 v^2 / g   = h      sub in the values   using g = 10 m/s^2

1/2 ( 7.5 )^2 / 10  = 2.8125 m

4 0
2 years ago
if jack was traveling north 120 miles and it took him 3 hours to get there. what is the velocity that jack was traveling? is thi
uysha [10]

Velocity of an object is given as

velocity = \frac{displacement}{time}

now we have

displacement = 120 miles

time = 3 hours

now from above formula

v = \frac{120}{3}

v = 40 miles/hour

so its velocity is 40 mph and its a vector quantity whose direction is towards NORTH

correct answer is B

7 0
4 years ago
a plane inclined at an angle of 30° to the horizontal has an efficiency of 50%. the force parallel to the plane required to push
Nutka1998 [239]

Answer:

Correct Answer: Option B

Explanation

V.R = 1sinθ=1sin30=21sinθ=1sin30=2

M.A = E×V.R100=50×2100=1E×V.R100=50×2100=1

Effort = loadM.A=1201=120N

3 0
3 years ago
Conduction
sashaice [31]

conducted

Conduction occurs when a substance is heated, particles will gain more energy, and vibrate more. These molecules then bump into nearby particles and transfer some of their energy to them. This then continues and passes the energy from the hot end down to the colder end of the substance.

7 0
3 years ago
You throw a baseball directly upward at time t = 0 at an initial speed of 12.3 m/s. What is the maximum height the ball reaches
Semmy [17]

Explanation:

At the maximum height, the ball's velocity is 0.

v² = v₀² + 2a(x - x₀)

(0 m/s)² = (12.3 m/s)² + 2(-9.80 m/s²)(x - 0 m)

x = 7.72 m

The ball reaches a maximum height of 7.72 m.

The times where the ball passes through half that height is:

x = x₀ + v₀ t + ½ at²

(7.72 m / 2) = (0 m) + (12.3 m/s) t + ½ (-9.8 m/s²) t²

3.86 = 12.3 t - 4.9 t²

4.9 t² - 12.3 t + 3.86 = 0

Using quadratic formula:

t = [ -b ± √(b² - 4ac) ] / 2a

t = [ 12.3 ± √(12.3² - 4(4.9)(3.86)) ] / 9.8

t = 0.368, 2.14

The ball reaches half the maximum height after 0.368 seconds and after 2.14 seconds.

5 0
4 years ago
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