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Stels [109]
3 years ago
9

Hahah I look pregnant don’t I

Physics
1 answer:
n200080 [17]3 years ago
8 0
I see a pillow

But you see...this bobcat
Cute ain’t it?

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The two waves shown below pass through the same medium in the phases shown and interfere with each other.
ale4655 [162]

A. W

Explanation:

The wave that would be produced by the interaction of the two waves shown in the diagram is wave W.

There is no wave in the diagram W.

This type of interference is known as destructive interference.

  • Destructive interference occurs when two waves out of phase comes together.
  • In this way, they cancel out each other and are terminated.
  • If the two waves are in phase, they will reinforce one another.
  • When waves reinforce one another, a constructive interference has occurred.

learn more:

Color in soap bubbles brainly.com/question/8733443

#learnwithBrainly

5 0
3 years ago
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If the height of the ramp was 1.2 m above the floor, how long would it take for the marble to hit the ground after it left the r
Evgesh-ka [11]
It would take at less 10 minte i guess this the right awnser

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3 years ago
Which group is the most common sedimentary rock
Llana [10]
Shale, sandstone, and limestone are the most commoc types of sedimentary rocks. They are formed by the most common mineral that is found on or near the surface of the Earth
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Define what is meant by restrictive interventions
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Medical movement for disabilities people
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A plank of length L=2.200 m and mass M=4.00 kg is suspended horizontally by a thin cable at one end and to a pivot on a wall at
baherus [9]

Hello!

Let's begin by doing a summation of torques, placing the pivot point at the attachment point of the rod to the wall.

\Sigma \tau = 0

We have two torques acting on the rod:
- Force of gravity at the center of mass (d = 0.700 m)

- VERTICAL component of the tension at a distance of 'L' (L = 2.200 m)

Both of these act in opposite directions. Let's use the equation for torque:
\tau = r \times F

Doing the summation using their respective lever arms:

0 = L Tsin\theta  - dF_g

dF_g = LTsin\theta

Our unknown is 'theta' - the angle the string forms with the rod. Let's use right triangle trig to solve:

tan\theta = \frac{H}{L}\\\\tan^{-1}(\frac{H}{L}) = \theta\\\\tan^{-1}(\frac{1.70}{2.200}) = 37.69^o

Now, let's solve for 'T'.

T = \frac{dMg}{Lsin\theta}

Plugging in the values:
T = \frac{(0.700)(4.00)(9.8)}{(2.200)sin(37.69)} = \boxed{20.399 N}

3 0
1 year ago
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