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likoan [24]
3 years ago
15

!!!!HURRY 30 POINTS!!!!

Physics
1 answer:
Nataly_w [17]3 years ago
3 0
The anwser is C flooding
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A motorcycle passes over the top of a hill that has a radius of curvature of 100 m. The mass of the motorcycle plus rider is 300
lorasvet [3.4K]

Answer:

F_N>F_N'

Explanation:

From the question we are told that

Radius of curvaturer=100m

Mass M=300kg

initial Speed of Motorcycle  V_1=30m/s

Final  Speed of Motorcycle  V_2=33m/s

Generally the equation Force at initial speed is  mathematically given as

F_N=mg-\frac{mv^2}{R}

F_N=300*9.8-\frac{(300*30)^2}{100}

F_N=240N

Generally the equation Force at Final speed is  mathematically given as

F_N'=mg-\frac{mv'^2}{R}

F_N'=300*9.8-\frac{(300*33)^2}{100}

F_N'=-327N

Therefore

F_N>F_N'

4 0
3 years ago
A resonant circuit using a 286-nFnF capacitor is to resonate at 18.0 kHzkHz. The air-core inductor is to be a solenoid with clos
lukranit [14]

Answer:

The inductor contains N = 523962.32 loops  

Explanation:

From the question we are told that

     The capacitance of the capacitor is  C =  286nF = 286 * 10^{-9} \  F

      The resonance frequency is  f = 18.0 kHz =  18*10^{3} Hz

       The diameter is  d =  1.1 mm = \frac{1.1 }{1000} = 0.00011 \ m

       The  of the air-core inductor is l = 12 \ m

        The permeability of free space is  \mu_o = 4 \pi *10^{-7} \ T \cdot m/A

 

Generally the inductance of this air-core inductor is mathematically represented as

              L =  \frac{\mu_o * N^2 \pi d^2}{4 l}

This inductance can also be mathematically represented as

               L = \frac{1}{w^2}

Where w is the angular speed mathematically given as

             w = 2 \pi f

So

            L =  \frac{1}{4 \pi ^2 f^2}

Now equating the both formulas for inductance

         \frac{\mu_o * N^2 \pi d^2}{4 l}  =  \frac{1}{4 \pi ^2 f^2}

making N the subject of  the formula

              N = \sqrt{\frac{1}{(2 \pi f)^2} * \frac{4 * l }{\mu_o * \pi d^2 C}  }

              N =  \frac{1}{2 \pi f} * \frac{2}{d} * \sqrt{\frac{l}{\pi * \mu_o * C} }

             

 Substituting value

            N =  \frac{1}{ 3.142  * 18*10^{3} * 0.00011 }  \sqrt{\frac{12}{ 3.142  * 4 \pi *10^{-7}* 286 *10^{-9}} }

              N = 523962.32 loops  

4 0
3 years ago
In an aligned and continuous carbon fiber-reinforced nylon 6,6 composite, the fibers are to carry 97% of a load applied in the l
drek231 [11]

Answer:

asdfghjkl

Explanation:

4 0
3 years ago
Read 2 more answers
Please answer this fast <br>I 'll marks them brainliest answer <br>​
Reptile [31]

answer

64 is C (c) 1-Bromo-3-methylbutane

63 is D

i is secondary ii is primary

8 0
3 years ago
a ferry which runs at 12m/s in still water travels between towns a and b on a river which flows south at 9 m/s. the ferry leavs
Reil [10]

Answer:

= 15 m/s

Explanation:

Considering right side(west) as positive x-axis and south as negative y-axis.

velocity of boat in still water v_b=12\hat{i}

velocity of stream v_s=-9\hat{j}

now relative velocity of boat w.r.t. stream v_{b/s}=12\hat{i}+9\hat{j}

this velocity with which ac distance will be covered.

therefore magnitude of v_{b/s} =\sqrt{12^2+9^2}

= 15 m/s

6 0
3 years ago
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