Plastics are marked as the most important factor in degrading of environment about three to five hundred years to decompose completely hence the more production of plastic the more is the adverse effect on the environment. Using recyclables plastic can decrease the production of plastic on daily basis thereby decreasing certain quantity of plastic that is present in the environment.
Hence maggie’s question should be reconstructed to form a scientific question in this way. How can using recyclable plastic reduce its exposure in environment?
Answer : <u>Natural</u>
Explanation : Natural resources are the resources that are found in the environment and are developed without the intervention of humans
Answer:
the final potential energy of this system is 3U0/10
Explanation:
We are given
charge at left end and another test charge at point p
Potential energy is given by = 
where k is electrostatics constant = 
Q1 = first charge , Q2= test charge
R= distance between charges
potential at point p
U0 = k*Q1*Q2 /3 ⇒ kq1q2 = 3U0 ..............1
now the test charge moves to point R
using Pytahgoreou theorem
R(distance) = 
= 10
New Potential energy
U1 = kq1*q2 / 10
substituting kq1q2 = 3U0 from 1
U1 = 3U0/10
So this is the final potential energy of this system.
Answer:
The final kinetic energy of the Helium nucleus (alpha particle) after been scattered through an angle of 120° is
8.00 x 10-13J
Explanation:
In Rutherford Scattering experiment, the collision of the helium nucleus with the gold nucleus is an ELASTIC COLLISION. This means that the kinetic energy is conserved ( The same before and after the collision).
Thus, the final kinetic energy of the helium nucleus is the same as initial kinetic energy (8.00 x 10^-13Joules)
Although, the kinetic energy is converted to potential energy in Coulomb's law equation.
That is,
1/2(mv^2) = (K* q1q2)/r
Where m is the mass of helium nucleus, v is its colliding velocity, k is electrostatic constant, q1 is the charge on helium nucleus, q2 is the charge on gold nucleus, r is impact parameter
For this case we have that by definition, the momentum is given by:
Where,
- <em>m: mass
</em>
- <em>v: speed
</em>
Therefore, replacing values we have:
From here, we clear the value of the speed:
Answer:
The magnitude of velocity is:
