Answer:
2 K(s) + Cl₂(g) ⟶ 2 KCl(s)
2 Cu(s) + O₂(g) ⟶ 2 CuO(s)
Explanation:
Both reactions are synthesis reactions (two substances combine to form another).
Reaction: K(s) + Cl₂(g) ⟶
The product is the binary salt KCl. The balanced chemical equation is:
2 K(s) + Cl₂(g) ⟶ 2 KCl(s)
Reaction: Cu(s) + O₂(g) ⟶
The most likely product is the metal oxide CuO. The balanced chemical equation is:
2 Cu(s) + O₂(g) ⟶ 2 CuO(s)
Explanation:
The given reaction equation is as follows.
The value of 
= 59.1 kJ/mol
We know that
,
or, 
= -(\frac{59.1 kJ/mol}{(8.314 \times 10^{-3} kJ/mol.K \times 310 K))}[/tex]
= -22.93
or, 
= 
![K_{sp} = [Ba^{2+}][ SO_{4}^{2-}]](https://tex.z-dn.net/?f=K_%7Bsp%7D%20%3D%20%5BBa%5E%7B2%2B%7D%5D%5B%20SO_%7B4%7D%5E%7B2-%7D%5D)
Therefore, ![[Ba^{2+}] =\sqrt{K_{sp}}](https://tex.z-dn.net/?f=%5BBa%5E%7B2%2B%7D%5D%20%3D%5Csqrt%7BK_%7Bsp%7D%7D)
= 
= 
Therefore, we can conclude that the value of ![[Ba^{2+}]](https://tex.z-dn.net/?f=%5BBa%5E%7B2%2B%7D%5D)
in the intestinal tract is .
Answer: 0.5 moles
Explanation:
Cr2(SO3)2 is the chemical formula for chromium sulphate.
Given that,
Amount of moles of Cr2(SO3)2 (n) = ?
Mass of Cr2(SO3)2 in grams = 128.9g
For molar mass of Cr2(SO3)2, use the atomic masses:
Chromium, Cr = 52g;
Sulphur, S = 32g;
Oxygen, O = 16g
Cr2(SO3)2 =
(52g x 2) + [(32g + 16g x 3) x 2]
= 104g + [(32g + 48g) x 2]
= 104g + [80g x 2]
= 104g + 160g
= 264g/mol
Since, n = mass in grams / molar mass
n = 128.9g / 264g/mol
n = 0.488 mole [Round the value of n to the nearest tenth which is 0.5
Thus, there are 0.5 moles in 128.9 grams of Cr2(SO3)2
There are 453.592 grams in a pound.
