Answer:
Cancer
Explanation:
Cancer is a genetic disease—that is, it is caused by changes to genes that control the way our cells function, especially how they grow and divide. Genetic changes that cause cancer can happen because: of errors that occur as cells divide.
Answer:
The Food Chain: The answer has to do with trophic levels. As you probably know, the organisms at the base of the food chain are photosynthetic; plants on land and phytoplankton (algae) in the oceans. These organisms are called the producers, and they get their energy directly from sunlight and inorganic nutrients.
Explanation:
Brainliest?
Answer:
You see the concentration decreased ten fold, from 1 M to 0.1 M.
You can simply increase the volume by ten times.
For example
If you have 250 mL of 1 molar HCl, you can add distilled water upto 2500 mL. Now the concentration is 0.1 molar.
If you want to use the serial dilution method, you can use the C1V1=C2V2 equation.
C1 = starting concentration.
C2 = final concentration.
V is for volume.
So let's say you have 500 mL of 1 M HCl and you only want 50 mL of 0.1 M HCl.
1 M x V1 = 0.1 M x 50 mL
V1 = 5 mL
So you take 5 mL of the original (stock) solution and dilute it up to 50 mL. Then you have 50 mL of 0.1 M HCl.
Explanation:
Answer:
(a) m = 50.916 g
(b) CO2 is the limiting reagent and C is the reagent in excess.
(c) the mass excess left = 4.084 g
Explanation:
Balance the given equation first:
(a) Given:
mass of CO2 = 40.0 g
mass of C = 15.0 g
mass of CO = ?
To find the mass of CO that will be produced, we need to find the limiting reactant first. To find the limiting reactant we will calculate the number of moles of each reactant, the reactant with less number of moles is the limiting reactant.
CO2:
n = m/M where m is the mass and M is the molar mass
n = 40.0g/44.01 g/mol
n = 0.909 mol
C:
n = m/M
n = 15.0 g/12,0107 g/mol
n = 1.249 mol
CO2 is the limiting reagent and C is the reagent in excess.
Grams of CO that will be produced:
The molar ratio between CO2 and CO is 1:2
Therefore the number of moles of CO = 0.909 x 2 = 1.818 mol
m = n x M
m = 1.818 mol x 28,01 g/mol
m = 50.916 g
(c) To find how much of the reagent in excess will be left we will use the stoichiometry
n = 0.909 mol
m = 0.909 mol x 12.0107 g/mol
m = 10.916 g
15.0 g - 10.916 g = 4.084 g
Therefore the mass excess left = 4.084 g