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Vesnalui [34]
3 years ago
11

How many moles are in 128.9 grams of Cr2(SO3)2?

Chemistry
1 answer:
Dominik [7]3 years ago
7 0

Answer: 0.5 moles

Explanation:

Cr2(SO3)2 is the chemical formula for chromium sulphate.

Given that,

Amount of moles of Cr2(SO3)2 (n) = ?

Mass of Cr2(SO3)2 in grams = 128.9g

For molar mass of Cr2(SO3)2, use the atomic masses:

Chromium, Cr = 52g;

Sulphur, S = 32g;

Oxygen, O = 16g

Cr2(SO3)2 =

(52g x 2) + [(32g + 16g x 3) x 2]

= 104g + [(32g + 48g) x 2]

= 104g + [80g x 2]

= 104g + 160g

= 264g/mol

Since, n = mass in grams / molar mass

n = 128.9g / 264g/mol

n = 0.488 mole [Round the value of n to the nearest tenth which is 0.5

Thus, there are 0.5 moles in 128.9 grams of Cr2(SO3)2

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Answer:

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3 years ago
What is the volume, in milliliters, occupied by 30.07 g of an object of density equal to
den301095 [7]

Answer:

\boxed {\tt 20.317567567568 \ mL}

Explanation:

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Let's rearrange the formula for v. the volume. Multiply both sides by v, then divide by d.

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Divide. Note, when dividing, the grams, or g will cancel out.

v= \frac{30.07}{1.48 \ mL}

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The volume of the object is 20.317567567568 milliliters.

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