All categories

3 years ago

Please help me this is due tomorrow thank you

Mathematics

2 answers:

GaryK [48]3 years ago

4 0

Answer: D

Step-by-step explanation:

The histogram shows driving to work so A even though it looks like it may fit there is no way to assume they don’t drive at all

Hope this helps

marusya05 [52]3 years ago

3 0

Answer:

The answer is option B.

Step-by-step explanation:

You might be interested in

Which is greater than or less than

Montano1993 [528]

Answer:

B. -1.44 IS GREATHER THEN -1.25

E. -2 3/4 IS GREATHER THEN -2.25

Step-by-step explanation:

6 0

4 years ago

Read 2 more answers

Which step is included in the construction of parallel lines?

umka21 [38]

Copy an angle by creating arcs with a compass

4 0

3 years ago

Read 2 more answers

Nick poured 3/4 fluid ounce of vineger into each ten 1-fluid -ounce test tubes test tubes to use in an experiment for Science Ni

Verizon [17]

Answer:

7.5 fluid ounces

Step-by-step explanation:

Fraction of fluid ounce poured into each test tube

Number of test tubes filled = 10

The number of fluid ounces poured is the product of the amount poured into each test tube and the number of test tubes filled

Therefore, total amount poured :

(3/4 fluid ounces) * 10

0.75 * 10

= 7.5 fluid ounces

4 0

3 years ago

The expression 12g

lbvjy [14]

34kilometers I think that is writght

4 0

4 years ago

Executives at a large multinational company are being accused of spending too much time on email and not enough time with their

Elena L [17]

Answer:

We conclude that there is not enough evidence to support the claim that company is spending too much time on email.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 96 minutes

Sample mean, $\bar{x}$ = 91 minutes

Sample size, n = 100

Alpha, α = 0.05

Sample standard deviation, s = 25 minutes

First, we design the null and the alternate hypothesis

$H_{0}: \mu \leq 96\text{ minutes}\\H_A: \mu > 96\text{ minutes}$

We use one-tailed t test to perform this hypothesis.

Formula:

$t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} }$

Putting all the values, we have

$t_{stat} = \displaystyle\frac{91 - 96}{\frac{25}{\sqrt{100}} } = -2$

Now, $t_{critical} \text{ at 0.05 level of significance, 99 degree of freedom } = 1.6603$

Since,

The calculated test statistic is less than the critical value, we fail to reject the null hypothesis and accept it.

Thus, we conclude that there is not enough evidence to support the claim that company is spending too much time on email.

6 0

4 years ago