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zimovet [89]
3 years ago
6

Please help me this is due tomorrow thank you

Mathematics
2 answers:
GaryK [48]3 years ago
4 0

Answer: D

Step-by-step explanation:

The histogram shows driving to work so A even though it looks like it may fit there is no way to assume they don’t drive at all

Hope this helps

marusya05 [52]3 years ago
3 0

Answer:

The answer is option B.

Step-by-step explanation:

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Hi!
suter [353]

Answer:

1 median=60.3

2 missing number=38

Step-by-step explanation:

1 45+55+76+y+88+54/6

316+y/6=63.6

316+x381.6

x=381.6-316=65.6

2M4 =63

60-62+92+x/4=63

214+x=252

x=252-214

=38

7 0
3 years ago
Read 2 more answers
1. Simplify the following by combining like terms (5 points).<br> 4x-10+14+7x-10x+2
ycow [4]

Answer:

X+6

Step-by-step explanation:

Combined like terms.

7 0
3 years ago
Read 2 more answers
Statisticians use ______ scores to divide the ______ under a curve the way people use a knife to cut pizza. Just as the pizza is
solong [7]

Answer:

Statisticians use z-scores to divide the area under a curve the way people use a knife to cut pizza.

Step-by-step explanation:

Statisticians use z-scores to divide the area under a curve the way people use a knife to cut pizza.

z-score:

  • A z-score is a numerical measurement which is measured in terms of standard deviations from the mean.
  • Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

  • If a z-score is 0, it tells that the data point is same as the mean.
  • Area under the normal curve is 1.
6 0
3 years ago
pamela claims that if you multiply a fraction that is negative by another fraction that is negative, the product will also be ne
svetoff [14.1K]
Pamela is incorrect. When you multiply anything negative by a negative, the product will always be a positive. Because the two negative signs cancel each other out.
5 0
3 years ago
Consider a particle moving along the x-axis where x(t) is the position of the particle at time t, x' (t) is its velocity, and x'
vodka [1.7K]

Answer:

a) v(t) =x'(t) = \frac{dx}{dt} = 3t^2 -12t +9

a(t) = x''(t) = v'(t) =6t-12

b)  0

c) a(t) = x''(t) = v'(t) =6t-12

When the acceleration is 0 we have:

6t-12=0, t =2

And if we replace t=2 in the velocity function we got:

v(t) = 3(2)^2 -12(2) +9=-3

Step-by-step explanation:

For this case we have defined the following function for the position of the particle:

x(t) = t^3 -6t^2 +9t -5 , 0\leq t\leq 10

Part a

From definition we know that the velocity is the first derivate of the position respect to time and the accelerations is the second derivate of the position respect the time so we have this:

v(t) =x'(t) = \frac{dx}{dt} = 3t^2 -12t +9

a(t) = x''(t) = v'(t) =6t-12

Part b

For this case we need to analyze the velocity function and where is increasing. The velocity function is given by:

v(t) = 3t^2 -12t +9

We can factorize this function as v(t)= 3 (t^2- 4t +3)=3(t-3)(t-1)

So from this we can see that we have two values where the function is equal to 0, t=3 and t=1, since our original interval is 0\leq t\leq 10 we need to analyze the following intervals:

0< t

For this case if we select two values let's say 0.25 and 0.5 we see that

v(0.25) =6.1875, v(0.5)=3.75

And we see that for a=0.5 >0.25=b we have that f(b)>f(a) so then the function is decreasing on this case.  

1

We have a minimum at t=2 since at this value w ehave the vertex of the parabola :

v_x =-\frac{b}{2a}= -\frac{-12}{2*3}= -2

And at t=-2 v(2) = -3 that represent the minimum for this function, we see that if we select two values let's say 1.5 and 1.75

v(1.75) =-2.8125< -2.25= v(1.5) so then the function sis decreasing on the interval 1<t<2

2

We see that the function would be increasing.

3

For this interval we will see that for any two points a,b with a>b we have f(a)>f(b) for example let's say a=3 and b =4

f(a=3) =0 , f(b=4) =9 , f(b)>f(a)

The particle is moving to the right then the velocity is positive so then the answer for this case is: 0

Part c

a(t) = x''(t) = v'(t) =6t-12

When the acceleration is 0 we have:

6t-12=0, t =2

And if we replace t=2 in the velocity function we got:

v(t) = 3(2)^2 -12(2) +9=-3

5 0
3 years ago
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