First we use sin(a+b)= sinacosb+sinbcosa
and cos(a+b)=cosa cosb -sinasinb
tan(x+pi/2)= sin(x+pi/2) / cos(x+pi/2)
and sin(x+pi/2) = sinxcospi/2 + sinpi/2cosx =cosx,
<span>cos(x+pi/2) = cosxcospi/2- sinxsinpi/2= - sinx,
</span> because <span>cospi/2 =0, </span>and <span>sinpi/2=1
</span><span>=tan(x+pi/2)= sin(x+pi/2) / cos(x+pi/2)= cosx / -sinx = -1/tanx = -cotx
</span>from where <span>tan(x+pi/2)=-cotx</span>
Answer:
There is one point: A (x, y) = (2, 0)
Step-by-step explanation:
A point of the square OABC is invariant only if its location coincides with location of the rotation axis, that is, that such point experiments only rotation, no translation in any form. The center of rotation coincides with the location of one of the vertices of the square and, therefore, there is one invariant point on the perimeter: A (x, y) = (2, 0)
Answer: 2
Step-by-step explanation:
I just did it on edge2020
The answer is C for that question
Answer: Skew lines are two lines that do not intersect and are not parallel. A simple example of a pair of skew lines is the pair of lines through opposite edges of a regular tetrahedron.
