Answer:
The coefficient for PH3 is 8. Option D is correct.
Explanation:
Step 1: The unbalanced equation
P2H4(g) ⇆ PH3(g) + P4(s)
Step 2: Balancing the equation
P2H4(g) ⇆ PH3(g) + P4(s)
On the left side we have 4x H (in P2H4), on the right side we have 3x H (in PH3). To balance the amount of H on both sides, we have to multiply P2H4 on the left side by 3 and PH3 on the right by 4.
3P2H4(g
) ⇆ 4PH3(g) + P4(s)
On the left side we have 6x P (in 3P2H4) on the right side we have 8x P (4x in 4PH3 and 4x in P4). To balance the amount of P on bot hsides, we have to multiply 3P2H4 by 2 and 4PH3 also by 2. Now the equation is balanced
6P2H4(g
) ⇆ 8PH3(g) + P4(s)
The coefficient for PH3 is 8. Option D is correct.
Answer:

-) Oxidizing agent: 
-) Reducing agent: 
Explanation:
The first step is separate the reaction into the <u>semireactions</u>:
A.
B.
If we want to balance in <u>basic medium </u>we have to follow the rules:
1. We adjust the oxygen with 
2. We adjust the H with 
3. We adjust the charge with 
Lets balance the first semireaction A. :

Now, lets balance semireaction B:

Finally, we have to add the two semireactions:
_________________________________________


_________________________________________


Cancel out the species on both sides:

Simplifying the equation :

The
is <u>oxidized</u> therefefore is the <u>reducing agent</u>. The
is<u> reduced</u> therefore is the <u>oxidizing agent</u>.
Answer:
the pressure at c = 0.27 atm
Explanation:
Given that:
number of moles (n) = 1.0 moles
Value of gamma in the monoatomic gas (γ) = 5/3
During an isothermal expansion, the volume at b is = 2.5 times the volume at a ; this implies that:

∴ To calculate the pressure at c from a; the process is adiabatic compression; so we apply:

![\frac{P_c}{P_a}=[\frac{V_a}{V_c}]^{(2/3)](https://tex.z-dn.net/?f=%5Cfrac%7BP_c%7D%7BP_a%7D%3D%5B%5Cfrac%7BV_a%7D%7BV_c%7D%5D%5E%7B%282%2F3%29)
![\frac{P_c}{1.0 atm}=[\frac{1}{2.5}]^{(2/3)](https://tex.z-dn.net/?f=%5Cfrac%7BP_c%7D%7B1.0%20atm%7D%3D%5B%5Cfrac%7B1%7D%7B2.5%7D%5D%5E%7B%282%2F3%29)

Thus, the pressure at c = 0.27 atm
Answer:
<h3>If the substance has high melting/boiling point, if it requires high temperature to dissociate into simpler particles, if it's structure is hard and if it conducts heat and electricity quite frequently, then it would be "Ionic compound" otherwise, it will be covalent compound.</h3>