Answer is: 89 g of CaCO₃ is <span>equired to prepare 50.0g of CaO.
</span>Chemical reaction: CaCO₃ → CaO + CO₂.
m(CaO) = 50,0 g.
m(CaCO₃) = ?
n(CaO) = m(CaO) ÷ M(CaO).
n(CaO) = 50,0 g ÷ 56 g/mol.
n(CaO) = 0,89 mol.
from reaction: n(CaCO₃) : n(CaO) = 1 : 1.
n(CaCO₃) = n(CaO).
n(CaCO₃) = 0,89 mol.
m(CaCO₃) = m(CaCO₃) · M(CaCO₃).
m(CaCO₃) = 0,89 mol · 100 g/mol
m(CaCO₃) = 89 g.
n - amount of substance.
Answer:
Check if the equipment is in a good condition.
Check if it can cause any harmful hazards.
Check if the equipment is what you need for the experiment
Element that forms more than one type of an electrically charged particle which is known as an ion.
A neutral atom has the same number of protons and electrons. Anytime an element has a charge, that means either more electrons or protons were added.
more electrons= negative charge
more protons = positive charge
Your charge is +3 which means there are 3 more protons than electrons
First answer is proton number is 21
The nucleon number means mass number which is protons + neutrons
24 + 21 = 45
Nucleon number is 45
Q=mcdeltaT. use this formula and find the answer.