Answer:
Correct option A.
The net force exerted by this loop on the straight wire with the current is directed TOWARDS THE LOOP
Explanation:
The magnetic field exerts a force on a current-carrying wire in a direction given by the right-hand rule 1 (the same direction as that on the individual moving charges). This force can easily be large enough to move the wire since typical currents consist of very large numbers of moving charges.
Given that,
The wire's current is directed towards the right of the page.
The rectangular loops carry current in a clockwise direction.
Since the 'dot' field is increasing hence the induced magnetic field is 'cross', i.e. into the page and by the right-hand rule, the induced current is clockwise.
Then the magnetic field is into the page.
Since was known that
F= iL×B
Note the current is through the wire. Then, the length is in direction of the current.
Note: this equation gives the magnetic force that acts on a length L of a straight wire carrying a current (i) and immersed in a uniform magnetic field (B), that is perpendicular to the wire.
So, the magnetic field is always perpendicular to the current.
So using right hand rule,
F = i(L×B)
The length is to the right i.e. +x direction and the Magnetic field is perpendicular to the plane, i.e. in the +z direction
F = i (L•i × B•k)
F = iLB (i×k)
F = iLB•(-j)
F = -iLB•j
Then, the force is in the negative y-direction i.e. towards the loop.
