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schepotkina [342]
4 years ago
11

HELP: When Jane drives to work, she always places her purse on the passenger's seat. By the time she gets to work, her purse has

fallen on the floor in front of the passenger seat. One day, she asks you to explain why this happens in terms of physics. What do you say?
Physics
1 answer:
Rudiy274 years ago
5 0

a force is a push or pull that acts upon an object as a result of its interaction with another object.  Newtons third law of motion suggests that something standing still will stay that way until another force pushes it.  This applies to Janes bag.  Every time Jane hits the brakes in her car, her bag will move forward until it finally falls off the seat.

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A person slaps her leg with her hand, bringing her hand to rest in 2.50 milliseconds from an initial speed of 4.00 m/s.
gtnhenbr [62]

Answer:

(a) 2400N

(b) Yes

Explanation:

(a) Mass (m) = 1.5kg, initial speed (v) = 4m/s, time (t) = 2.5milliseconds = 2.5/1000 = 0.0025seconds

F = mv/t = (1.5×4)/0.0025 = 6/0.0025 = 2400N

(b) The force would be different because the mass of the two hands and forearms is 3kg (2 × 1.5kg = 3kg)

4 0
3 years ago
PLEASE HELP!!!!!!!!!!!!!!!!
Nesterboy [21]

The correct answer is - It is the part of the ocean where new crusts are formed.

The place marked with A on the map is the place in the ocean where the new crust is formed. That is a place where there's a divergent plate boundary, or rather a place where the tectonic plates are moving away from one another. The gap and cracks left between them are easy target for the magma from the mantle to penetrate towards the surface. As the magma reaches the ocean floor it starts to cool off very quickly, creating new crust, and slowly making a very large underwater mountain range known as mid-ocean ridge.

7 0
4 years ago
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A car travels up a hill at a constant speed of 22 km/h and returns down the hill at a constant speed of 55 km/h. calculate the a
Ket [755]
The answer choice is 2.5
6 0
3 years ago
You are operating a pwc. you are heading straight toward a dock. you turn the engine off and then turn the steering control hard
White raven [17]
In this case, the PWC will head for the dock. This is because, power needs to be applied in order to maintain steering control. If the throttle is left to idle or if the engine is turn off during operation, all steering control will be lost. In each of this situation, the PWC will continue in the was headed before the engine was turned off or before the throttle was left to idle.  
6 0
4 years ago
Two workers are sliding 300 kg crate across the floor. One worker pushes forward on the crate with a force of 400 N while the ot
almond37 [142]

Answer:

The kinetic coefficient of friction of the crate is 0.235.

Explanation:

As a first step, we need to construct a free body diagram for the crate, which is included below as attachment. Let supposed that forces exerted on the crate by both workers are in the positive direction. According to the Newton's First Law, a body is unable to change its state of motion when it is at rest or moves uniformly (at constant velocity). In consequence, magnitud of friction force must be equal to the sum of the two external forces. The equations of equilibrium of the crate are:

\Sigma F_{x} = P+T-\mu_{k}\cdot N = 0 (Ec. 1)

\Sigma F_{y} = N - W = 0 (Ec. 2)

Where:

P - Pushing force, measured in newtons.

T - Tension, measured in newtons.

\mu_{k} - Coefficient of kinetic friction, dimensionless.

N - Normal force, measured in newtons.

W - Weight of the crate, measured in newtons.

The system of equations is now reduced by algebraic means:

P+T -\mu_{k}\cdot W = 0

And we finally clear the coefficient of kinetic friction and apply the definition of weight:

\mu_{k} =\frac{P+T}{m\cdot g}

If we know that P = 400\,N, T = 290\,N, m = 300\,kg and g = 9.807\,\frac{m}{s^{2}}, then:

\mu_{k} = \frac{400\,N+290\,N}{(300\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)}

\mu_{k} = 0.235

The kinetic coefficient of friction of the crate is 0.235.

5 0
3 years ago
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