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Alex_Xolod [135]

3 years ago

10

The gas waste generated by many power plants is

2 answers:

Andrej [43]3 years ago

8 0

The answer to your question is sulfur oxide. I hope I helped!!

lapo4ka [179]3 years ago

5 0

carbon dioxide

is the answer

You might be interested in

A mass m is attached to a spring which is held stretched a distance x by a force f (fig. 7-28), and then released. the spring co

guapka [62]

Spring is stretched by force f to distance "x"

now here by force balance we can say

$f = kx$

$k = \frac{f}{x}$

now here we will we say that energy stored in the spring will convert into kinetic energy

$\frac{1}{2} kx^2 = \frac{1}{2}mv^2$

$\frac{f}{x} (x^2} = mv^2$

now solving above equation we will have

$v =\sqrt{ \frac{fx}{m}}$

PART 2)

now for half of the extension again we can use energy conservation

$\frac{1}{2}kx^2 - \frac{1}{2}k(x/2)^2 = \frac{1}{2} mv^2$

$\frac{3}{4}kx^2 = mv^2$

$\frac{3}{4}fx = mv^2$

now the speed is given as

$v = \sqrt{\frac{3fx}{4m}}$

5 0

3 years ago

Read 2 more answers

A boy flying a kite is standing 30 ft from a point directly under the kite. if the string to the kite is 50 ft long, what is the

vagabundo [1.1K]

Draw a diagram to illustrate the problem as shown in the figure below.
h = height of the kite above ground.

By definition, the angle of elevation is
$cos \theta = \frac{30}{50} =0.6$
Therefore
$\theta = cos^{-1} 0.6 = 53.1 \, deg.$

Answer: 53° (nearest integer)

3 0

3 years ago

Could someone please please help meee

Kobotan [32]

Explanation:

noo she has potencial i think kinetic is just if shes moving and shes just about to jump so i think is no

4 0

1 year ago

A basketball of mass 0.608 kg is dropped from rest from a height of 1.37 m. It rebounds to a height of 0.626 m.

kenny6666 [7]

Answer:

a) $|\Delta E|=4.58\: J$

b) $F=61.90\: N$

Explanation:

a)

We can use conservation of energy between these heights.

$\Delta E=mgh_{2}-mgh_{1}=mg(h_{2}-h_{1})$

$\Delta E=0.608*9.81(0.6026-1.37)$

Therefore, the lost energy is:

$|\Delta E|=4.58\: J$

b)

The force acting along the distance create a work, these work is equal to the potential energy.

$W=\Delta E$

$F*d=mgh$

Let's solve it for F.

$F=\frac{mgh}{d}$

$F=\frac{0.608*9.81*1.37}{0.132}$

Therefore, the force is:

$F=61.90\: N$

I hope is helps you!

6 0

2 years ago

With what minimum speed must you toss a 110 g ball straight up to just touch the 11-m-high roof of the gymnasium if you release

Sholpan [36]

Answer:

v = 13.79 m/s

Explanation:

given,

mass of ball = 110 g

height = 11 m

ball is released from = 1.3 m

minimum speed = ?

using conservation of energy

Potential energy is conserved in the form of kinetic energy

$P E =KE$

$m g h= \dfrac{1}{2}mv^2$

$v^2 = 2 g h$

$v=\sqrt{2 g h}$

$v=\sqrt{2\times 9.8 \times (11-1.3)}$

$v=\sqrt{2\times 9.8 \times 9.7}$

$v=\sqrt{190.12}$

v = 13.79 m/s

7 0

3 years ago