I think the correct answer would be D. After cutting the solid object in half, the mass and volume are both divided by two, but the density remains the same. The mass and volume would change accordingly to satisfy the law of conservation of mass which states that mass cannot be created or destroyed. So, after dividing the object the sum of the mass of the two parts should be equal to the original mass of the object. This would also be the same for the volume of the objects. Density is the ratio of mass and volume and, since the mass and volume change accordingly, the value of the density would still be the same regardless of the object being divided.
Answer:
w = 0.189 rad/ s
Explanation:
This exercise we work with the conservation of the moment, the system is made up of the merry-go-round and the child, for which we write the moment of two instants
Initial
L₀ = I₀ w₀
Final
= I w
L₀ = L_{f}
I₀ w₀ = I_{f} w
.w = I₀/I_{f} w₀
The initial moment of inertia is
I₀ = 500 kg. m2
The final moment of inertia
= 500 + m r²
I_{f} = 500 + 20 1.5
I_{f} = 530 kg m²
Initial angular velocity
w₀ = 0.20 rad / s
Let's calculate
w = 500/530 0.20
w = 0.189 rad / s
Hi, thank you for posting your question here at Brainly.
This problem could be solved using this equation:
Diffraction limit = 1.22*wavelength/diameter
diameter = 0.8 cm = 0.008 m
wavelength = 500E-9 m
Diffraction limit = 1.22(500E-9)/0.008
Diffraction limit = 0.00007625
Answer:
the rate of heat transfer after the system achieves steady state is -3.36 kW
Explanation:
Given the data in the question;
mass of water m = 50 kg
N = 300 rpm
Torque T = 0.1 kNm
V = 110 V
I = 2 A
Electric work supplied W₁ = PV = 2 × 110 = 220 W = 0.22 kW
Now, work supplied by paddle wheel W₂ is;
W₂ = 2πNT/60
W₂ = (2π × 0.1 × 300) / 60
W₂ = 188.495559 / 60
W₂ = 3.14 kW
So the total work will be;
W = 0.22 + 3.14
W = 3.36 kW
Hence total work done on the system is 3.36 kW.
At steady state, the properties of the system does not change so the heat transfer will be 3.36 KW.
The heat will be rejected by the system so the sign of heat will be negative.
i.e Q = -3.36 kW
Therefore, the rate of heat transfer after the system achieves steady state is -3.36 kW
Answer:
Velocity of Sedan = 21 m/s
Velocity of SUV = 12 m/s
Explanation:
As we know that deceleration due to friction force is given as

so we have


now the two cars comes to rest at a point which is at position of 5.39 m West and 6.43 m South
so net displacement of the car is given as


now the velocity of the two cars just after the impact is given as



direction of the motion is given as

South of West
now we can use momentum conservation as there is no external force on it
Momentum conservation in North to south direction



Similarly momentum conservation towards West direction


