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Amiraneli [1.4K]
3 years ago
10

An alpha particle consists of two protons and two neutrons with a mass of 6.64 x 1027 kg and charge 3.2 x 10-19 C. If two of the

m are separated by a distance R, using Coulomb's Law and the Universal Law of Gravitation, calculate the ratio of the electric force to the gravitational force acting on each. Do you think this is a surprising number?
Physics
1 answer:
Dafna11 [192]3 years ago
8 0

Answer:  ratio = 3.14 × 10³⁵

Explanation:

From Newtons law of Universal Gravitation;

Every object in the universe is attracted to every other object

F = (Gm₁m₂)/r²

G = 6.67 X 10⁻¹¹ N-m²/kg²

M₁= mass of one object

M₂= mass of second object

r = distance from center of objects

q = charge = 3.2 x 10⁻¹⁹C.

  • Calculating the gravitational force;

Fg = (Gm₁m₂)/r² = (Gm²)/r²

which is = (6.67×10⁻¹¹ × (6.64×10⁻²⁷)²) / r²

= (2.94 × 10⁻⁶³) / r²

  • Calculating the electric force;

Fe = (Kq₁q₂) / r² = K q² / r² = (9×10⁹ × (3.2 × 10⁻¹⁹)² / r²

Fe = 9.22 × 10⁻²⁸ / r²

comparing the ratio of both forces we have;

Fe/Fg = (9.22×10⁻²⁸/r²) ÷ (2.94×10⁻⁶³/r²)

r² cancels from the above expression, which gives;

ratio as 3.14 × 10³⁵

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disa [49]

Answer:

Nonrenewable Resources

8 0
3 years ago
While traveling along a highway a driver slows from 32 m/s and comes to a stop with an acceleration of -6 m/s2. How long did it
diamong [38]

Answer: 6s

Explanation:

Vs=32m/s  speed at beginning of slowing down

Vf=0m/s     stop speed

a= -6 m/s²  acceleration

----------------

Use equation for acceleration :

a=(Vf-Vs)/t

a*t=Vf-Vs

t=(Vf-Vs)/a

t=(0-36)/-6

t=-36/-6

t=6 s

7 0
3 years ago
A radio wave has a frequency of 5.5 × 104 hertz and travels at a speed of 3.0 × 108 meters/second. What is its wavelength?
tigry1 [53]

Answer:5.45X10^3m

Explanation:So use the formula,v= fλ

3X10^8=5.5X10^4λ what Im saying is divide both and u should get 5454.54m but do sig figs to get answer

3 0
3 years ago
Read 3 more answers
Vector A has a magnitude 5 m, vector B has a magnitude 7 m. Which of the following cannot be the magnitude of the vector A + B?
bulgar [2K]
I think it should be 7m
7 0
4 years ago
A ball of mass 0.250 kg and a velocity of + 5.00 m/s collides head-on with a ball of mass 0.800 kg that is initially at rest. No
Mademuasel [1]

Answer:

v_1=-2.616\ m/s

Explanation:

Given that,

Mass of ball 1, m_1=0.25\ kg

Initial speed of ball 1, u_1=5\ m/s

Mass of ball 2, m_2=0.8\ kg

Initial speed of ball 2, u_2=0 (at rest)

After the collision,

Final speed of ball 2, v_2=2.38\ m/s

Let v_2 is the final speed of ball 1.

Initial momentum of the system is :

p_i=m_1u_1+m_2u_2

p_i=0.25\times 5+0

p_i=1.25\ m/s

Final momentum of the system is :

p_f=m_1v_1+m_2v_2

p_f=0.25\times v_1+0.8\times 2.38

p_f=0.25 v_1+1.904

According the law of conservation of linear momentum :

initial momentum = final momentum

1.25=0.25 v_1+1.904

v_1=-2.616\ m/s

So, the final velocity of ball 1 is (-2.616)m/s.

8 0
3 years ago
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