The Silence of the Lambs ends when Hannibal Lecter, from a payphone in the tropics, congratulates FBI Academy graduate Clarice Starling and gently warns her not to hunt him, ending the call by saying he had to go because he was having a friend for dinner, as he watched his hospital tormenter, Dr. Chilton, disembark from a plane. While that nervous laugh allowed movie goers to summon the courage to leave the theater and run to their cars, the original ending scripted by Tally gave no such quarter. When Lecter speaks to Starling, he compliments her outfit, which makes her realize he had watched from a distance. In the original ending, Lecter is cutting orange segments with a small paring knife, while he speaks to Clarice. As he hangs up the phone, the camera shot widens. We discover that he”s at a desk in a book lined office. There is the body of a bodyguard on the floor, and then we see Lecter is not alone. Chilton is trussed up in a chair across from him, the same method of restraints the doctor used on Lecter earlier in the movie. Lecter rises, slowly, a dreamy gleam in his eye, as he approaches his terrified victim, paring knife in hand. “Shall we begin?”
Explanation:
Below is an attachment containing the solution.
Entropy is an extensive property of a thermodynamic system. It quantifies the number Ω of microscopic configurations (known as microstates) that are consistent with the macroscopic quantities that characterize the system (such as its volume, pressure and temperature).[1] Under the assumption that each microstate is equally probable, the entropy
S
S is the natural logarithm of the number of microstates, multiplied by the Boltzmann constant
For t1:
t1 = square root of 2h1 / g = square root of 2 * 0.5 / 9.8 = 0.319 sec
For t2:
t2 = sqaure root of 2h2 / g = square root of 2 * 1.0 / 9.8 = 0.451 sec
Wherein:
t = time(s) for the vertical movement
h= height
g = gravity (using the standard 9.8 m/sec measurement)
d1 = 1*0.319 = 0.319 m
d2 = 0.5 * 0.451 = 0.225 m
Where:
d = hor. distance
ratio = d1:d2
= 0.319 : 0.225
=3.19 : 2.25
The answer is 3.19 : 2.25
Answer:
Their velocity after the collision is 1.2 m/s, to the right.
Explanation:
Given;
mass of the blue car, m₁ = 2 kg
initial velocity of the blue car, u₁ = 6 m/s
mass of the red car, m₂ = 3 kg
initial velocity of the red car, u₂ = 2 m/s
let the blue car moving to the right be in positive direction
also, let the red car moving to the left be in negative direction
Apply the principle of conservation of linear momentum for inelastic collision.
m₁u₁ - m₂u₂ = v(m₁ + m₂)
where;
v is their velocity after the collision
(2 x 6) - (3 x 2) = v(2 + 3)
12 - 6 = 5v
6 = 5v
v = 6/5
v = 1.2 m/s, to the right
Therefore, their velocity after the collision is 1.2 m/s, to the right.
