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jeyben [28]
3 years ago
11

Given that a person with normal hearing can barely detect a sound with intensity of 1 dB at a frequency of 1 kHz (the sensitivit

y of the human ear peaking near 1 kHz), how far away could this person detect another person breathing normally?

Physics
1 answer:
dimaraw [331]3 years ago
8 0

Answer:

Answer = 3.16m

Explanation:

The concept applied here is the relationship between intensity and sound level. the intensity I of a sound wave is the average rate per unit area at which energy is transferred.

I = P/A

I = intensity

A = Area

The intensity of a sound wave can also be expressed in terms of the decibel scale. DB is the abbreviation for decibel which is the unit of sound level this was named after Alexander Graham bell whose work on this aspect was recognized.

The step by step calculation and necessary derivations is a shown in the attachment.

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3 years ago
You throw a stone upward from the top of a building at an angle of 25° to the horizontal and with an initial speed of 15 m/s. I
Alex787 [66]

Answer:

11.025 m

87.75 m

Explanation:

Time of flight(T) of a projectile = 2U(sin∅)/g

Where U = initial Velocity, g = acceleration due to gravity, ∅= angle of projection.

Make ∅ the subject of the the equation,

∅ = sin⁻¹[(T× g)/2U]

Where U = 15m/s, T= 3.0 s, g = 9.8 m/s²

∅ = sin⁻¹[(3 × 9.8)/(2×15)]

∅ = sin⁻¹(29.4/30)

∅= sin⁻¹(0.98) = 78.52°

Using the formula for maximum height of a projectile

H = U²sin²∅/2g

H = 15²(sin²78.52)/2 × 9.8

H = 225(0.98 × 0.98)/19.6

H = 216.09/19.6

H = 11.025 m

Range (R) = U²sin2∅/g

R = 15²sin(2×79.52)/9.8

R = 225(0.39)

R =87.75 m

∵ the building is = 11.025 m tall and the base of the building is 87.75m away from where the stone landed.

6 0
4 years ago
5
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Answer:

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Explanation:

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Explanation:

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F = ma solve for m .......
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You should solve this like you would any algebraic expression.  Divide both sides by acceleration (a) and you will isolate the mass (m) to one side.  Now divide the force (f) by acceleration (a).

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