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igomit [66]
3 years ago
13

5

Physics
2 answers:
KiRa [710]3 years ago
7 0
D, the wheels
Jdjdhdhddvsjksjdvx
NNADVOKAT [17]3 years ago
4 0

Answer:

D

Explanation:

moving car experience the most is the Tyre

You might be interested in
2. A 2kg body attached to a spring undergoes a SHM of amplitude 0.4m and period
Rudik [331]

Answer:

a) 12.8 N

b) 3.2 m/s²

Explanation:

I'm guessing the period is 0.5π s.

Period of a spring in simple harmonic motion is:

T = 2π √(m/k)

Given T = 0.5π and m = 2 kg:

0.5π = 2π √(2/k)

0.25 = √(2/k)

0.0625 = 2/k

k = 32

The spring constant is 32 N/m, and the maximum displacement is 0.4 m.  The maximum force can be found with Hooke's law:

F = kx

F = (32 N/m) (0.4 m)

F = 12.8 N

The acceleration can be found with Newton's second law:

∑F = ma

kx = ma

(32 N/m) (0.2 m) = (2 kg) a

a = 3.2 m/s²

8 0
3 years ago
there is only one basic format for a professional report. a. audience b. All of these should be considered when deciding on a re
Anna007 [38]

Answer:

The answer is letter b. All of these should be considered when deciding on a report format.

Explanation:

A Professional Report is a type of formal document about a topic or information that is intended for a specific audience or purpose. The report's style of writing needs a lot of knowledge from the writer. Oftentimes, it involves the following important elements: <em>Title, Summary, Body, Discussion, Conclusion and Recommendation. </em>

The writer should write according to his target audience and purpose. He also needs to consider the length of his report, as well as the suitable words and sentences that he should use.

Thus, all of the choices are important in writing a professional report. So, the answer is letter b.

5 0
3 years ago
A parachutist of mass 20.1 kg jumps out of an airplane at a height of 662 m and lands on the ground with a speed of 7.12 m/s. Th
Klio2033 [76]

Answer:

1.30\cdot 10^5 J

Explanation:

The energy lost due to air friction is equal to the mechanical energy lost by the parachutist during the fall.

The initial mechanical energy of the parachutist (at the top) is equal to his gravitational potential energy:

E_i=mgh

where

m = 20.1 kg is his mass

g=9.8 m/s^2 is the acceleration due to gravity

h = 662 m is the initial heigth

The final mechanical energy (at the bottom) is equal to his kinetic energy:

E_f=\frac{1}{2}mv^2

where

v = 7.12 m/s is the final speed of the parachutist

Therefore, the energy lost due to air friction is:

\Delta E=E_i-E_f=mgh-\frac{1}{2}mv^2=(20.1)(9.8)(662)-\frac{1}{2}(20.1)(7.12)^2=1.30\cdot 10^5 J

4 0
4 years ago
As the frequency of the ac voltage across a capacitor approaches zero, the capacitive reactance of that capacitor:___________.
sergij07 [2.7K]

Answer:

B) approaches infinity

Explanation:

The capacitive reactance of an AC capacitor is given by;

X_C = \frac{1}{\omega C } = \frac{1}{2\pi f C}

Where;

C is the capacitance

f is the frequency of the ac voltage

X_C = \frac{1}{\omega C} = \frac{1}{2\pi f C} \\\\X_C = \frac{1}{2\pi f C} \\\\X_C = \frac{1}{2\pi (0) C} \\\\X_C = \frac{1}{0} \\\\X_C = \ infinity

Therefore, as the frequency of the ac voltage across a capacitor approaches zero, the capacitive reactance of that capacitor approaches infinity.

The correct option is (B) approaches infinity

7 0
3 years ago
For trapezoid JKLM, A and B are midpoints of the legs. Find AB.
kodGreya [7K]

Answer:

AB = 29

Explanation:

For a better understanding, we must work this problem in a graphic way. In the attached image we can see the solution.

First, we draw a vertical dotted lines from the point J & K to the line ML, then we can see two new portions with the same length. Then with this simple analysis:

2x = 39 - 19

x = 10

Then we know that x = 10, another important data to find the answer is that the AB line is located in the midpoints of the legs. We also can see the right triangle MJ and the dotted line.

Now for every single right triangle, no matter its size and relationship between the vertical and the horizontal lengths, if some point is located in the hypotenuse (leg) at the middle of its length. This will be proportional to the vertical and the horizontal cathetus, therefore we will have the middle point on those two lines.

So, the AB line will be the sum of JK plus two times 5

AB = 19 + 5 + 5 = 29

7 0
4 years ago
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