Answer:
Distance traveled during this acceleration will be 6950 m
Explanation:
Wear have given maximum speed tat will be equal to final speed of the car v = 278 m/sec
Constant acceleration
As the car starts initially starts from rest so initial velocity of the car u = 0 m/sec
From third equation of motion
Putting all values in equation
s = 6950 m
So distance traveled during this acceleration will be 6950 m
<u>Answer</u>: The potential difference across the resistor is 12 volts.
<u>Explanation:</u>
To calculate the potential difference cross the resistor, we use Ohm's Law. This law states that the potential difference across two wires is directly proportional to the current flowing through that wire.
Mathematically,
Where,
V = potential difference = ?V
I = Current flowing = 1.2 A
R = Resistor =
Putting values in above equation, we get:
Hence, the potential difference across the resistor is 12 volts
Answer:
<em>The distance the car traveled is 21.45 m</em>
Explanation:
<u>Motion With Constant Acceleration </u>
It occurs when an object changes its velocity at the same rate thus the acceleration is constant.
The relation between the initial and final speeds is:
Where:
a = acceleration
vo = initial speed
vf = final speed
t = time
The distance traveled by the object is given by:
Solving [1] for a:
Substituting the given data vo=0, vf=6.6 m/s, t=6.5 s:
The distance is now calculated with [2]:
x = 21.45 m
The distance the car traveled is 21.45 m
Answer:
Explanation:
the relation between current, voltage and resistance in an electrical circuit is given by Ohm's law:
where V is the voltage, I is the current and R is the resistance. In this problem, the current is I=2 A, the voltage is V=120 V, therefore we can arrange the previous equation and find the resistance: