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Salsk061 [2.6K]
3 years ago
13

A student stays at her initial position for a bit of time, then walks slowly in a straight line for a while, then stops to rest

a while, and finally runs quickly back to her initial position along a straight line. Which of the following statements is true about the average speed and the magnitude of the average velocity of the student during her trip? Her average speed is greater than the magnitude of her average velocity. Her average speed is the same as the magnitude of her average velocity. Her average speed is less than the magnitude of her average velocity. The student's average speed and velocity cannot be compared without knowing the farthest point she reached.
Physics
1 answer:
IRINA_888 [86]3 years ago
5 0

Answer:Average speed is greater than average velocity.

Explanation  :

Given

student walks slowly along a straight line for a while ,then stops to rest a while, and finally runs quickly back to her initial position

Let x be the length of track and the whole process takes t time

For average speed =\frac{distance\ traveled}{time\ taken}

Average speed=\frac{2x}{t}

For average velocity =\frac{Displacement}{time\ taken}

Since displacement is zero as she returns to its initial position.

Average velocity=0

Therefore Average speed is greater than average velocity.

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A 16-Ω loudspeaker, an 8.0-Ω loudspeaker, and a 4.0-Ω loudspeaker are connected in parallel across the terminals of an amplifier
kolbaska11 [484]

Answer:

2.286 ohm

Explanation:

R1 = 16 ohm

R2 = 8 ohm

R3 = 4 ohm

They all are connected in parallel combination

Let the equivalent resistance is R.

1/R = 1/R1 + 1/R2 + 1/R3

1/R = 1/16 + 1/8 + 1/4

1/R = (1 + 2 + 4) / 16

1/R = 7 / 16

R = 16/7 = 2.286 ohm

6 0
4 years ago
7) If the mass of an object is 694 g, find the mass of rider 1 if rider 2 = 600g rider 3 = 90 (Subtract the smaller numbers from
icang [17]

The mass of the rider 1 is 4 g.

<h3>The use of a rider in mass measurement</h3>

Rider is a metallic wire piece which is of certain mass and can be bent . It can move the beam of the Paul Bunge Balance.

The riders are the sliding pointers positioned on top of the beams to show the pan and beam weight in grams.

<h3>Mass of the rider 1</h3>

The mass of the rider 1 is obtained by subtracting mass of riders as show below.

mass of rider 1 = mass of object - (mass of rider 2 + mass of rider 3)

mass of rider 1 = 694 g  - (600 g + 90 g)

mass of rider 1 = 694 g - 690 g

mass of rider 1 = 4 g

Thus, the mass of the rider 1 is 4 g.

Learn more about use of riders in mass measurement here: brainly.com/question/1747339

#SPJ1

8 0
2 years ago
Where can Microsoft users browse forums by topic, search existing questions and answers, or ask their own questions?
adoni [48]

Group of answer choices.

A. Community and Forum Resources.

B. Get Live Help.

C. Tech Specs.

D. Top Support Issues.

Answer:

A. Community and Forum Resources.

Explanation:

Microsoft is a multinational corporation that designs and develops various types of software applications or programs such as Microsoft operating system (OS), Microsoft Word, Microsoft Excel, Microsoft Access, Microsoft PowerPoint, etc., to avail end users the ability to perform different tasks on their computers.

Whenever these users encounter a problem with any of these software applications or programs, they can easily go to the official forums and communities to get help from professionals and other end users who may have experienced such problems in the past. These community and forums are typically interactive in nature and as such serves its purpose often times.

Hence, Microsoft users can browse forums by topic, search existing questions and answers, or ask their own questions on Community and Forum Resources.

3 0
3 years ago
Water flows through a water hose at a rate of Q1 = 860 cm3/s, the diameter of the hose is d1 = 1.85 cm. A nozzle is attached to
Snowcat [4.5K]

Answer:

a) A1 =  \frac{\pi (d1)^{2} }{4}

b) A1 = 2.688 cm^{2}

c) Q1 = A1 x v1

d) v1 = 3.1994 m/s

e) A2 = \frac{A1 X v1}{v2}

f)  A2 = 0.7963cm^{2}

Explanation:

a) Area = \pi r^{2}

r = \frac{d}{2}

thus,

area = \pi (\frac{d}{2})^{2}

A1 =  \frac{\pi (d1)^{2} }{4}[/tex]b) d1 = 1.85 cmsubstituting in the above equation,A1 =  [tex]\frac{\pi (d1)^{2} }{4}

A1 =  \frac{\pi (1.85)^{2} }{4}

A1 = 2.688 cm^{2}

c) Flow rate = Area x velocity ( refer brainly.com/question/13997998)

Q1 = A1 x v1

d) From the above equation,

v1 = \frac{Q1}{A1} = \frac{860}{2.688} = 319.94 cm/s = 3.1994 m/s

e) Since the flow rate Q1 is constant throughout the hose, Av is a constant.

i.e. A1 x v1 = A2 x v2

thus,

A2 = \frac{A1 X v1}{v2}

f) v2 = 10.8 m/s.

substituting the values in the above equation,

A2 = \frac{2.688 X 3.1994}{10.8}  = 0.7963cm^{2}

3 0
4 years ago
PLEASE HELP ASAP!!!!
sveticcg [70]

Answer:

it's frequency

Explanation:

hope this helps :)

8 0
3 years ago
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