F = ma solve for m .......
2 answers:
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Answer:
a)1.93 kg-m^2
b) 1.45 kg-m^2
c) = 0
d) 1.15 kg-m^2
Explanation:
mass of the bar M = 4 kg
length of the bar = 2 m
mass of balls m1= m2= 0.3 kg
moment of inertia of bar
about an axis perpendicular to the bar through its center.
a) MOI of bar + 2×m×(L/2)^2
+
now putting the values of m, M and L as above and solving we get
I= 1.93 kg-m^2
b) perpendicular to the bar through one of the balls
= 1.45 kg-m^2
c) parallel to the bar through both balls
zero as the no mass distribution along the parallel to the bar through both balls.
d) parallel to the bar and 0.500 m from it.
I=
putting values and solving we get
1.15 kg-m^2
Answer:
Height reached will be 28.35 m
Explanation:
Here we can use the work energy theorem to find the maximum height
As we know by work energy theorem
Work done by gravity + work done by friction = change in kinetic energy
now we will have
so here the height raised by the stone will be 28.35 m from the ground after projection in upward direction