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3 years ago

SECTION-D

Mathematics

1 answer:

expeople1 [14]3 years ago

7 0

Answer:

For the triangle having the sides 122m, 120m and 22m :

122+120+22

=132m

Area of triangle =

s(s−a)(s−b)(s−c)

132(132−122)(132−120)(132−22)

132×10×12×110

=1320m

For the triangle having the sides 22m, 24m and 26m :

22+24+26

=36m

36(36−22)(36−24)(36−26)

36×14×12×10

=24

105

=24×10.25m

(approx.)=246m

There, the area of the shaded portion

=(1320−246)m

=1074 m

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