1 answer:
Answer:
For the triangle having the sides 122m, 120m and 22m :
s=
2
122+120+22
=132m
Area of triangle =
s(s−a)(s−b)(s−c)
=
132(132−122)(132−120)(132−22)
=
132×10×12×110
=1320m
2
For the triangle having the sides 22m, 24m and 26m :
s=
2
22+24+26
=36m
=
36(36−22)(36−24)(36−26)
=
36×14×12×10
=24
105
=24×10.25m
2
(approx.)=246m
2
There, the area of the shaded portion
=(1320−246)m
2
=1074 m
2
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