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Goshia [24]
3 years ago
9

The recommended daily intake of potassium (K) is 4.725 grams. The avergae raisin contains 3.677 mg K. Assuming that each raisin

contains 3.677 milligrams, how many raisins per day would a person need to eat to meet the recommended daily amount of K from consuming raisins alone?
Chemistry
2 answers:
levacccp [35]3 years ago
7 0
<span>3.677mg =</span>0,003677g \ \ \ \ \ \ \ \ \Rightarrow  \ \ \ \ \ \ \ 1 \ raisin\\&#10;4,725g \ \ \ \ \ \ \ \ \ \ \ \ \Rightarrow \ \ \ \ \ \ \ \ x\\\\&#10;x=\frac{4,725g*1}{ 0,003677g}\approx 1285 \ raisins


tino4ka555 [31]3 years ago
5 0

<u>Answer:</u> A person should consume 1285 raisins per day.

<u>Explanation:</u>

It is given that the total intake of potassium for a person is 4.725 grams and a contains an average of 3.677 mg of potassium in it.

We need to find the total number of raisins that a person must consume in order to have the daily intake of potassium.

For, this we require a conversion factor:

1g=1000mg\\\\3.677mg=\frac{3.677}{1000}=0.003677g

To calculate the number of raisins, we divide the total intake by the amount of potassium one raisin contain, we get:

n\times 0.003677=4.725\\\\n=\frac{4.725}{0.003677}=1285

Hence, a person should consume 1285 raisins per day.

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