Answer:
S4N2
Explanation:
good luck have a nice day
In writing chemical reactions, it is important that you know the chemical formula of each substance and in balancing them, it should be that the number of each element in both side are equal.
2K(s) + 2H2O(l) = 2KOH(aq) + H2(g)
From other sources, the given mass of the solute that is being dissolved here is 7.15 g Na2CO3 - 10H2O. We use this amount to convert it to moles of Na2CO3 by converting it to moles using the molar mass then relating the ratio of the unhydrated salt with the number of water molecules. And by the dissociation of the unhydrated salt in the solution, we can calculate the moles of Na+ ions that are present in the solution.
Na2CO3 = 2Na+ + CO3^2-
7.15 g Na2CO3 - 10H2O (1 mol / 402.9319 g) (1 mol Na2CO3 / 1 mol Na2CO3 - 10H2O) ( 1 mol Na2CO3 / 1 mol Na2CO3-10H2O ) ( 2 mol Na+ / 1 mol Na2CO3) = 0.04 mol Na+ ions present
Answer:
Methane -1,Ethene 2 , Ethane 2,Pentane 5,Propene 3,Hexane 6,Ethyne 2,Propane 3,Octane 8,Heptane 7 Decane 10,Butyne 4,Butane 4,Propyne 3,Butene 4
Matte because it is harder to take off
