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Dmitrij [34]
3 years ago
8

Help pls!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics
2 answers:
nordsb [41]3 years ago
8 0

Answer:

B. x = 4,2

Rewriting the equation into factored form:

{x}^{2}  - 6x + 8 = 0 \\  {x}^{2}  -2x - 4x + 8 = 0 \\  ({x}^{2}  -2x) + (-4x +8) = 0 \\ x(x - 2) - 4(x -2) = 0 \\ (x -2) (x - 4) = 0

Finding the value of x using zero product property:

x - 2 = 0 \\ x =  2

x -4 =0  \\ x  = 4

Komok [63]3 years ago
3 0
The answer is X = 4, 2
You can even plug those in for X to check your answer.
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Drag the values to order them from least to greatest, with the least at the top. Item 2 moved to position 3. 79 − − √ + 63 − − √
Nonamiya [84]

\sqrt{63} \\ \\ \sqrt{79}  \\ \\ \sqrt{143} \\ \\ 4\pi

<h2>Explanation:</h2>

As I understand, in this exercise, we have the following numbers:

\text{Number 1}=\sqrt{79} \\ \\ \text{Number 2}=\sqrt{63} \\ \\ \text{Number 3}=\sqrt{143} \\ \\ \text{Number 4}=4\pi

By using calculator, let's convert those numbers into decimal form:

\text{Number 1} \approx 8.88\\ \\ \text{Number 2} \approx 7.93 \\ \\ \text{Number 3} \approx 11.96 \\ \\ \text{Number 4} \approx 12.56

So arranging from least to greatest we have:

\text{Number 2} \\ \\ \text{Number 1} \\ \\ \text{Number 3} \\ \\ \text{Number 2}

Put another way:

\sqrt{63} \\ \\ \sqrt{79}  \\ \\ \sqrt{143} \\ \\ 4\pi

7 0
3 years ago
Calculate the mass of sodium azide (2NaN3) required to decompose and produce 1.20 moles of nitrogen.
Ad libitum [116K]

Answer:

The answer to your question is:  40.8 g of NaN₃

Step-by-step explanation:

NaN₃ mass = ?

nitrogen = 1.2 moles

Equation

                           2NaN₃      ⇒ 2Na  +  3N2

                          2 moles of NaN₃  -----------------   3 moles of N₂

                           x                          ------------------   1.2 moles of N₂

                          x = (1.2 x 2) / 3

                          x = 2.4/ 3

                         x = 0.8 moles of NaN₃

MW NaN₃ = 23 + 28

                = 51 g

                         51 g of NaN₃ ----------------- 1 mol

                         x                    ----------------- 0.8 mol

                         x = (0.8 x 51) / 1

                        x = 40.8 g of NaN₃

3 0
3 years ago
The product of three and a square number is twice the sum of the number and four
alex41 [277]
Write an equation, calling the number x:

3x=2(x+4)

3x=2x+8

x=8

However, 8 is not a perfect square, which was required in the problem, so there are no solutions.
5 0
3 years ago
Simplify 8.9 - 1.4x + (-6.5x) + 3.4
lesya692 [45]

Answer:

12.3 - 7.9x

Step-by-step explanation:

8.9 - 1.4x + (-6.5) +3.4

12.3 - 1.4x - 6.5=

12.3 - 7.9x

8 0
3 years ago
Solve:
Misha Larkins [42]

Answer:

convert 3 1/3 to an improper fraction

3*3 = 9

9+1 = 10

10/3

multiply the numerator by 4

(10/3) * 4 = 40/3

40/3 = 13 1/3

5 0
3 years ago
Read 2 more answers
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