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4 years ago

What is the common ratio for this geometric sequence? 5,15,45,135...

Mathematics

1 answer:

LiRa [457]4 years ago

5 0

Answer:

Step-by-step explanation:

To find the common ration, we take the 2nd term and divide it by the first term

15/5 = 3

Let check by taking the third term and dividing by the 2nd term

45/15 =3

The common ratio is 3

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Perform the indicated operation. Be sure the answer is reduced.

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<h3>Given Equation:-</h3>

$\boxed{ \rm \frac{4x^{2}y^{3}z}{9} \times \frac{45y}{8 {x}^{5} {z}^{5} }}$

<h3>Step by step expansion:</h3>

$\dashrightarrow \sf\dfrac{4x^{2}y^{3}z}{9} \times \dfrac{45y}{8 {x}^{5} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{ \cancel4x^{2}y^{3}z}{9} \times \dfrac{45y}{ \cancel8 {x}^{5} {z}^{3} }$

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$\dashrightarrow \sf\dfrac{x^{2}y^{3}z}{9} \times \dfrac{45y}{2{x}^{5} {z}^{3} }$

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$\dashrightarrow \sf\dfrac{x^{2}y^{3}z}{ \cancel9} \times \dfrac{ \cancel{45}y}{2{x}^{5} {z}^{3} }$

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$\therefore \underline{ \textbf{ \textsf{option \red c \: is \: correct}}}$

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