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4 years ago

What does the atomic mass come from on the periodic table

Chemistry

2 answers:

kap26 [50]4 years ago

8 0

Answer:

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Explanation:

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KIM [24]4 years ago

5 0

Answer:

Explanation: Atomic Mass is the mass of the atom. It is usually expressed in kilograms. It is almost equal to the sum of the number of protons and neutrons present in the atom.

The protons and neutrons of an atom are present in the nucleus itself and electrons are revolving around the nucleus.

In the periodic table, the elements are arranged according to their atomic properties. Atomic mass or mass number is written on the upper left side and atomic number is written on the lower right hand side.

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What is emitted during gamma radiation?

LenKa [72]

Packets of energy called gamma particles

5 0

3 years ago

Volume of 15.1 grams of silver

boyakko [2]

Answer:

10.5

Explanation:

8 0

4 years ago

Silver has a resistance of 0.0198 ohms. What voltage would produce a current of 100 amps? ______________

nekit [7.7K]

Explanation:

V=IR

r=0.0198

i=100

v=0.0198×100

=1.98 volts

7 0

3 years ago

An industrial synthesis of urea obtains 87.5 kg of urea upon reaction of 68.2 kg of ammonia with excess carbon dioxide. Determin

dolphi86 [110]

Answer:

The theoretical yield of urea = <u>120.35kg</u>

The percent yield for the reaction = <u>72.70%</u>

Explanation:

Lets calculate -

The given reaction is -

$2NH_3(aq)+CO_2$ → $CH_4N_2O(aq)+H_2O (l)$

Molar mass of urea $CH_4N_2O$ = 60g/mole

Moles of $NH_3$ = $\frac{62.8kg/mole}{17g/mole}$ (since $Moles=\frac{mass of substance}{mass of one mole}$ )

= 4011.76 moles

Moles of $CO_2$ = $\frac{105kg}{44g/mole}$

= $\frac{105000g}{44g/mole}$

= 2386.36 moles

Theoritically , moles of $NH_3$ required = double the moles of $CO_2$

but , $4011.76$ , the limiting reagent is $NH_3$

Theoritical moles of urea obtained = $\frac{1 mole CH_4N_2O}{2mole NH_3}\times4011.76 mole NH_3$

= $2005.88mole CH_4N_2O$

Mass of 2005.88 mole of $CH_4N_2O$ = $2005.88 mole \times\frac{60g CH_4N_2O}{1mole CH_4N_2O}$

= 120352.8g

$120352.8g\times \frac{1kg}{1000g}$

= 120.35kg

Therefore , theroritical yeild of urea = 120.35kg

Now , Percent yeild = $\frac{87.5kg}{120.35kg}\times100$

72.70%

Thus , the percent yeild for the reaction is 72.70%

8 0

3 years ago

Which method can you use to investigate the compressibility of a gas?

Alina [70]

Answer: Option (b) is the correct answer.

Explanation:

It is known that in a gas, molecules are away from each other due to more kinetic energy between its particles. As a result, there are more number of collisions between them.

So, when we apply pressure on a gas then its molecules come closer to each other. Due to which there occurs decrease in its volume.

Thus, we can conclude that to investigate the compressibility of a gas increase the pressure on it.

3 0

3 years ago