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antiseptic1488 [7]
4 years ago
15

What does the atomic mass come from on the periodic table

Chemistry
2 answers:
kap26 [50]4 years ago
8 0

Answer:

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Explanation:

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sven!

KIM [24]4 years ago
5 0

Answer:

Explanation: Atomic Mass is the mass of the atom. It is usually expressed in kilograms. It is almost equal to the sum of the number of protons and neutrons present in the atom.

The protons and neutrons of an atom are present in the nucleus itself and electrons are revolving around the nucleus.

In the periodic table, the elements are arranged according to their atomic properties. Atomic mass or mass number is written on the upper left side and atomic number is written on the lower right hand side.

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Packets of energy called gamma particles
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Volume of 15.1 grams of silver
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Answer:

10.5

Explanation:

8 0
4 years ago
Silver has a resistance of 0.0198 ohms. What voltage would produce a current of 100 amps? ______________
nekit [7.7K]

Explanation:

V=IR

r=0.0198

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v=0.0198×100

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7 0
3 years ago
An industrial synthesis of urea obtains 87.5 kg of urea upon reaction of 68.2 kg of ammonia with excess carbon dioxide. Determin
dolphi86 [110]

Answer:

The theoretical yield of urea = <u>120.35kg</u>

The percent yield for the reaction = <u>72.70%</u>

Explanation:

Lets calculate -

The given reaction is -

2NH_3(aq)+CO_2 →CH_4N_2O(aq)+H_2O (l)

Molar mass of urea CH_4N_2O= 60g/mole

Moles of NH_3 = \frac{62.8kg/mole}{17g/mole} (since Moles=\frac{mass  of  substance}{mass of one mole})

                     = 4011.76 moles

Moles of CO_2 = \frac{105kg}{44g/mole}

                = \frac{105000g}{44g/mole}

                = 2386.36 moles

Theoritically , moles of NH_3 required = double the moles of CO_2

    but , 4011.76 , the limiting reagent is NH_3

Theoritical moles of urea obtained = \frac{1 mole CH_4N_2O}{2mole NH_3}\times4011.76 mole NH_3

                                                      = 2005.88mole CH_4N_2O

Mass of 2005.88 mole of CH_4N_2O =2005.88 mole \times\frac{60g CH_4N_2O}{1mole CH_4N_2O}

                                                     = 120352.8g

                                                     120352.8g\times \frac{1kg}{1000g}

                                                     = 120.35kg

Therefore , theroritical yeild of urea = 120.35kg

Now , Percent yeild = \frac{87.5kg}{120.35kg}\times100

                                 72.70%

Thus , the percent yeild for the reaction is 72.70%

8 0
3 years ago
Which method can you use to investigate the compressibility of a gas?
Alina [70]

Answer: Option (b) is the correct answer.

Explanation:

It is known that in a gas, molecules are away from each other due to more kinetic energy between its particles. As a result, there are more number of collisions between them.

So, when we apply pressure on a gas then its molecules come closer to each other. Due to which there occurs decrease in its volume.

Thus, we can conclude that to investigate the compressibility of a gas increase the pressure on it.

3 0
3 years ago
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