Answer:
The theoretical yield of urea = <u>120.35kg</u>
The percent yield for the reaction = <u>72.70%</u>
Explanation:
Lets calculate -
The given reaction is -
→
Molar mass of urea = 60g/mole
Moles of = (since )
= 4011.76 moles
Moles of =
=
= 2386.36 moles
Theoritically , moles of required = double the moles of
but , , the limiting reagent is
Theoritical moles of urea obtained =
=
Mass of 2005.88 mole of =
= 120352.8g
= 120.35kg
Therefore , theroritical yeild of urea = 120.35kg
Now , Percent yeild =
72.70%
Thus , the percent yeild for the reaction is 72.70%