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Pepsi [2]
3 years ago
7

When Barium chloride is formed, what questions will the student need to know prior to making the formula???

Chemistry
1 answer:
guapka [62]3 years ago
3 0

Answer:

Valency of the two elements

Explanation:

In order to correctly formularize the compound, the student needs to ask of the valences of the elements involved.

Chlorine has valency of -1, while Barium +2.

The exchange of valency gives the formula BaCl_{2}.

Another explanation is that Barium donates 2 electrons which the chlorine atoms accept, in order to form the covalent bond.

I hope this was helpful.

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What is the minimum % relative error for a 0.5M NaOH solution?
scZoUnD [109]

Answer: 20%

Explanation:

Relative error = Absolute error/actual value

= 0.1/0.5

= 0.2

Hence,

Minimum % Relative error = 0.2 ×100%

= 20%

4 0
4 years ago
Read 2 more answers
How many molecules are in 165 g of carbon dioxide?
Svet_ta [14]
М(СО₂)=165 г

н(СО₂)=м(углекислого газа)/М(СО₂)

Н=Nₐ*м(углекислого газа)/М(СО₂)

Н=6.022*1023 * 165/44.01=2.258*10²⁴
6 0
3 years ago
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H2(g) + F2(g)2HF(g) Using standard thermodynamic data at 298K, calculate the entropy change for the surroundings when 2.20 moles
abruzzese [7]

<u>Answer:</u> The value of \Delta S^o for the surrounding when given amount of hydrogen gas is reacted is -31.02 J/K

<u>Explanation:</u>

Entropy change is defined as the difference in entropy of all the product and the reactants each multiplied with their respective number of moles.

The equation used to calculate entropy change is of a reaction is:

\Delta S^o_{rxn}=\sum [n\times \Delta S^o_{(product)}]-\sum [n\times \Delta S^o_{(reactant)}]

For the given chemical reaction:

H_2(g)+F_2(g)\rightarrow 2HF(g)

The equation for the entropy change of the above reaction is:

\Delta S^o_{rxn}=[(2\times \Delta S^o_{(HF(g))})]-[(1\times \Delta S^o_{(H_2(g))})+(1\times \Delta S^o_{(F_2(g))})]

We are given:

\Delta S^o_{(HF(g))}=173.78J/K.mol\\\Delta S^o_{(H_2)}=130.68J/K.mol\\\Delta S^o_{(F_2)}=202.78J/K.mol

Putting values in above equation, we get:

\Delta S^o_{rxn}=[(2\times (173.78))]-[(1\times (130.68))+(1\times (202.78))]\\\\\Delta S^o_{rxn}=14.1J/K

Entropy change of the surrounding = - (Entropy change of the system) = -(14.1) J/K = -14.1 J/K

We are given:

Moles of hydrogen gas reacted = 2.20 moles

By Stoichiometry of the reaction:

When 1 mole of hydrogen gas is reacted, the entropy change of the surrounding will be -14.1 J/K

So, when 2.20 moles of hydrogen gas is reacted, the entropy change of the surrounding will be = \frac{-14.1}{1}\times 2.20=-31.02J/K

Hence, the value of \Delta S^o for the surrounding when given amount of hydrogen gas is reacted is -31.02 J/K

7 0
3 years ago
What is the pH of a solution with [H-] = 4.3 x 10-4 M?
Temka [501]

Answer:

3.37

Explanation:

pH=-log(H3O+)

- Hope that helps! Please let me know if you need further explanation.

4 0
4 years ago
For the following experiments, identify the independent variable and the dependent variable:
faust18 [17]

Answer:

A) IV: number of hours DV: score

Explanation:

Coz,

IV- is the variable that u change

DV- is the variable that u test or measure

In this case, we need to change the hours of studying to see how studying for different hours [1 hr, 2hr, etc (( Independant variable coz we're changing the no. of hours)) ] is going to affect the student's score, and in the end, we are measuring the score of each student [this is the dependant variable].

3 0
3 years ago
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