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kap26 [50]
3 years ago
13

Which atomic model was proposed as a result of J. J. Thomson’s work?

Chemistry
2 answers:
lesya692 [45]3 years ago
4 0
The answer would be A) The plum pudding model.
victus00 [196]3 years ago
4 0

Answer: Option (a) is the correct answer.

Explanation:

J.J. Thomson is a renowned scientist who discovered the model of atom which is known as the plum pudding model.

Through this model Thomson stated that an atom consists of small particles. These small particles are positive and negative charges present inside an atom.

Whereas Democritus stated that an atom is indivisible and thus he proposed the indivisible atom model.

Ernest Rutherford discovered that an atom has lot of empty space and this space is nucleus. As he stated that positively charged particles are known as protons which are present inside a nucleus.

Rutherford's gold foil experiment discovered that an atom has nucleus in which most of the mass of an atom is concentrated.

Thus, we can conclude that the plum pudding model was proposed as a result of J. J. Thomson’s work.

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Label the spin–spin splitting that you would expect to observe in the nmr spectrum of 1-methoxypropane. not all labels will be u
Snezhnost [94]
The structure of 1-methoxypropane is CH₃-CH₂-CH₂-OCH₃

I will label the carbons A-D from left to right.

A      B     C        D
CH₃-CH₂-CH₂-OCH₃

In a proton NMR spectrum, we are looking at the chemical shifts of each unique hydrogen atom, and the splitting patterns tell us how many hydrogens are attached to the adjacent carbon. Therefore, the signal from the protons on carbon A will be split by the protons on carbon B, and the signal for protons on carbon A will have a splitting pattern equal to n+1, where n = number of hydrogens on the adjacent carbon.

Therefore, for the protons on carbon A, there are two neighbouring protons and these will give a splitting patter of 3 peaks, also known as a triplet.

Protons on carbon A: 2 adjacent protons result in a triplet signal.

Protons on carbon B: 5 adjacent protons result in a sextet signal.

Protons on carbon C: 2 adjacent protons result in a triplet signal.

Protons on carbon D: 0 adjacent protons result in a singlet signal.
6 0
4 years ago
Convert 6.62 X 10^23 atoms to moles
olga2289 [7]

Answer:

1.099

Explanation:

Hope this helps

5 0
3 years ago
Read 2 more answers
The metric system is also known as the
slega [8]

Answer:

THE answer is all of above

Explanation:

3 0
3 years ago
Read 2 more answers
6. Write the ICE chart for the reaction of 32.0 g of sulfur and 71.0 g of chlorine: S8 + 4 Cl24S2Cl2 After completing the chart
Marianna [84]

Answer:

ICE Table Figure

a. 67.37 g S_2Cl_2

b. 35.62 g Cl_2

c. 58.61 gS_2Cl_2

Explanation:

For the <u>ICE table </u>we have to keep in mind that we have 4 moles of Cl_2 and 1 mol of S_8 and the reactives are consumed, so for Cl_2 we will have -4X and for S_8 we will have -X. Follow the same logic we will have -4X for S_2Cl_2.

a. <u>Mass of the product</u>

Molar mass of S_8= 256.52 g/mol

Molar mass of Cl_2=70.9 g/mol

Molar mass of S_2Cl_2=135.03 g/mol

We have to find the limiting reagent in the reaction:

S_8+4Cl_2->4S_2Cl_2

\frac{32}{256.52}=0.124molS_8

\frac{71}{70.9}=1 molCl_2

Divide by the coefficients in the balanced reaction:

\frac{0.124}{1}=0.124mol

\frac{1}{4}=0.25 mol

The limiting reagent would be S_8

Now is posible to calculate the amount of S_2Cl_2 produced:

0.124molS_8\frac{4molS_2Cl_2}{1 molS_8}\frac{135.03gS_2Cl_2}{1 molS_2Cl_2}=67.37gS_2Cl_2

b. <u>Mass  in excess</u>

0.124molS_8\frac{4molCl_2}{1 molS_8}\frac{70.9gCl_2}{1 molCl_2}=35.38gCl_2

Excess\hspace{0.1cm}=\hspace{0.1cm}71gCl_2-35.38gCl_2=35.62 gCl_2

C. <u>87%Yield</u>

67.37gS_2Cl_2\frac{87}{100}=58.61gS_2Cl_2

5 0
3 years ago
What is the uncertainty of a 10ml pipet?​
EleoNora [17]

Answer: the certain of a 10ml pipet is listed as, 10.00 0.02,

Explanation: those numbers are close to 4 significant figures as in (10ml) around the amount you're looking for. , hope that makes sense!

3 0
3 years ago
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