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Nutka1998 [239]
4 years ago
11

Name and describe two of the basic characteristics of living organisms

Physics
1 answer:
IceJOKER [234]4 years ago
8 0
The basic characteristics of living organisms can be reminded by using DR. R. COG one characteristic for each letter:
D- It has Dna or genetic material in its cells.
R- It has the ability to Reproduce
R- It Responds to the environment, this helps it survive easily
C- The Cell is its basic unit
O- It Obtains energy from some type of source
G- It Grows and develops with the passing of the time
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Motion can be detected by using background objects that are not moving called_______________ points
gtnhenbr [62]

Answer: A reference point

Explanation: If an object is in motion then its distance from another object is changing.  Whether an object is moving or not depends on your point of view. For example, a woman riding on a bus is not moving in relation to the seat she is sitting on, but she is moving in relation to the buildings the bus passes. A reference point is a place or object used for comparison to determine if something is in motion. An object is in motion if it changes position relative to a reference point. You assume that the reference point is stationary, or not moving.

8 0
3 years ago
If you want to double the kinetic energy of a gas molecule, by what factor must you increase its momentum?A) 16B) 2^(1/2)
worty [1.4K]

Answer: \sqrt{2}

The linear momentum p is given by the following equation:

p=m.v   (1)

Where m is the mass and v the velocity.

On the other hand, the kinetic energy K is given by:

K=\frac{p^{2}}{2m}   (2)

Which is the same as:

K=\frac{1}{2}m.v^{2}

Now, if we double the kinetic energy, equation (2) changes to:

2K=2\frac{p^{2}}{2m}  

2K=\frac{p^{2}}{m}   (3)

So, if we want to obtain the kinetic energy as shown in (3), the only option that works is increasing momentum by a factor of \sqrt{2} or 2^{1/2}:

Applying this in (2):

K=\frac{(\sqrt{2}p)^{2}}{2m}

K=\frac{(2p)^{2}}{2m}

K=\frac{p^{2}}{m}>>>As we can see, this equation is the same as equation (3)

Therefore, the correct answer is B

3 0
3 years ago
A stretched rubber band has ___________ energy. a. elastic kinetic energy b. gravitational potential energy c. elastic potential
densk [106]

Answer: Option (c) is the correct answer.

Explanation:

An elastic object is defined as the object that is able to retain its shape when a force is applied on it.

For example, when we pull a rubber band then it stretches and when we withdraw the force applied on it then it retain its shape.

As we know that potential energy is the energy obtained by an object due to its position.

So, when we stretch a rubber band then it will have elastic potential energy as position of the rubber band is changing and since, it will retain it shape hence it has elastic potential energy.

Thus, we can conclude that a stretched rubber band has elastic potential energy.

3 0
4 years ago
1. Two balloons are charged with an identical quantity and type of charge: -6.25C. They are held apart at a separation distance
Degger [83]

Answer:

The electric force between them is 878.9 N

Given:

Identical charge C

Separation between two charges  m

For finding the electrical force,

According to the coulomb's law

Here, force between two balloons are repulsive because both charges are same.

Where    N  Therefore, the electric force between them is 878.

Explanation:

4 0
2 years ago
At surface level, a diving bell has an air space of 4.25 m3. When used during an exploration, it is submerged 60.0 metres. At th
Alinara [238K]

Answer:

volume of the airspace=0.605m^3

Explanation:

Patm = 10^5 N/m^2

Depth= 60 metres

Pressure at the depth = ?

Density = 1.025 g/cm3 = 1025 kg/m3

P = Patm + hσg

P = 10^5 + 60*1025*9.8

P = 702700 N/m^2

P = 7.027 atm

Since the temperature is constant, Boyle’s law holds

P1V1 = P2V2

P1 = 1 atm  

P1, initial pressure of the bell(atm pressure) = 1 atm

The initial volume of the airspace, V1 = 4.25 m^3

Final pressure at the depth = 7.027 atm

Applying the Boyle’s lay

1*4.25 = 7.027 * V2

V2 = 4.25/7.027

V2 = 0.605m^3

8 0
4 years ago
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