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Mazyrski [523]
3 years ago
6

Another nervous papa bear paces at 1.0 m/s north for 3.0 s, then at 1.6 m/s south for 5.0 s, and then

Physics
1 answer:
lozanna [386]3 years ago
8 0

Answer:

Explanation:

Average speed is total distance traveled over the time needed to do so.

d = vt

v = (1.0(3.0) + 1.6(5.0) + 1.4(4.0) / (3.0 + 5.0 + 4.0)

v = 16.6 / 12

v = 1.383333333...

v = 1.4 m/s

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A 210 g block is dropped onto a relaxed vertical spring that has a spring constant of k = 2.0 N/cm. The block becomes attached t
Yuliya22 [10]

Answer:

a) W_{g}=mdx = 0.21 kg *9.8\frac{m}{s^2} 0.10m=0.2058 J

b) W_{spring}= -\frac{1}{2} Kx^2 =-\frac{1}{2} 200 N/m (0.1m)^2=-1 J

c) V_i =\sqrt{2 \frac{W_g + W_{spring}}{0.21 kg}}}=\sqrt{2 \frac{(1-0.2058)}{0.21 kg}}}=2.75m/s

d)  d_1 =0.183m or 18.3 cm

Explanation:

For this case we have the following system with the forces on the figure attached.

We know that the spring compresses a total distance of x=0.10 m

Part a

The gravitational force is defined as mg so on this case the work donde by the gravity is:

W_{g}=mdx = 0.21 kg *9.8\frac{m}{s^2} 0.10m=0.2058 J

Part b

For this case first we can convert the spring constant to N/m like this:

2 \frac{N}{cm} \frac{100cm}{1m}=200 \frac{N}{m}

And the work donde by the spring on this case is given by:

W_{spring}= -\frac{1}{2} Kx^2 =-\frac{1}{2} 200 N/m (0.1m)^2=-1 J

Part c

We can assume that the initial velocity for the block is Vi and is at rest from the end of the movement. If we use balance of energy we got:

W_{g} +W_{spring} = K_{f} -K_{i}=0- \frac{1}{2} m v^2_i

And if we solve for the initial velocity we got:

V_i =\sqrt{2 \frac{W_g + W_{spring}}{0.21 kg}}}=\sqrt{2 \frac{(1-0.2058)}{0.21 kg}}}=2.75m/s

Part d

Let d1 represent the new maximum distance, in order to find it we know that :

-1/2mV^2_i = W_g + W_{spring}

And replacing we got:

-1/2mV^2_i =mg d_1 -1/2 k d^2_1

And we can put the terms like this:

\frac{1}{2} k d^2_1 -mg d_1 -1/2 m V^2_i =0

If we multiply all the equation by 2 we got:

k d^2_1 -2 mg d_1 -m V^2_i =0

Now we can replace the values and we got:

200N/m d^2_1 -0.21kg(9.8m/s^2)d_1 -0.21 kg(5.50 m/s)^2) =0

200 d^2_1 -2.058 d_1 -6.3525=0

And solving the quadratic equation we got that the solution for d_1 =0.183m or 18.3 cm because the negative solution not make sense.

5 0
3 years ago
How many significant digits should the answer to the following problem have? (2.49303 g) * (2.59 g) / (7.492 g) =
Feliz [49]

The number of significant digits to the answer of the following problem is four.

<h3>What are the significant digits?</h3>

The number of digits rounded to the approximate integer values are called the significant digits.

The following problem is

(2.49303 g) * (2.59 g) / (7.492 g) =

On solving we get

= 0.86184566204

The answer is approximated to  0.86185

Thus, the significant digits must be four.

Learn more about significant digits.

brainly.com/question/1658998

#SPJ1

6 0
2 years ago
Compare the planets Mars and Saturn. Describe how their common characteristics are similar and Compare the planets Earth and Nep
nordsb [41]

Question no. 1. Compare the planets Mars and Saturn. Describe how their common characteristics are similar:

Answer:  Our solar system is located in the outer spiral arm of the milky way galaxy. our solar system has one sun and nine revolving planets and . namely  

  1. Mercury
  2. Venus
  3. Earth
  4. Mars
  5. Jupiter
  6. Saturn
  7. Uranus
  8. Neptune
  9. Pluto (small planet usually refer as dwarf)

Each star has its on moon/moons and has its own characteristics i.e , planet must be a celestial body , must have orbit around sun, have enough mass for self gravity, big enough to have gravity that clear its path from other same size object close to its orbit around sun.

Mars is the fourth from the sun and sixth is the Saturn from the sun in our solar system.

<u>Common in Characteristics of Mars and Saturn:</u>

  • Mars and Saturn both have celestial body.
  • Mars and Saturn both have enough mass for the gravity to get rid of rigid body forces.
  • Mars and Saturn both revolve around the sun in their own orbits.
  • Mars is the second smallest in the solar system while Saturn is second largest in the solar system.
  • Mars and Saturn both have their own moons. Mars has two while Saturn has 83 moons
  • Mars and Neptune both do not support life.    

Question no. 2. Compare the planets Earth and Neptune. Describe how are they different from each other

Answer:

Earth our home planet is the third from the sun and Neptune on the other hand is the eighth from the sun in the solar system.

<u>Common differences between Earth and Neptune</u>

  • Earth is the terrestrial planet while Neptune (Ice giant) is the Jovian planet.
  • Earth has no ring around it, Neptune has ring around it.
  • Earth is closer to the sun and Neptune is far distant from the sun.
  • Earth consists of rocks and metals on the other hand Neptune contain gases
  • Earth is smaller than the Neptune in the solar system.
  • Earth rotates slower and Neptune rotates faster.
4 0
3 years ago
A 2.50-m segment of wire carries 1000 A current and feels a 4.00-N repulsive force from a parallel wire 5.00 cm away. What is th
Stolb23 [73]

Answer:

The current is  I_b  =  400 \ A

Explanation:

From the question we are told that

    The  length of the segment is  l  =  2.50  \  m

     The current is  I_a  =  1000 \ A

     The force felt is  F  =  4.0 \  N

        The distance of the second wire is  d =  5.0 \ cm  = 0.05 \  m

Generally the current on the second wire is mathematically represented as

        I_b  =  \frac{2 \pi * r * F }{ l *  \mu_o  *  I_a }

Here  \mu_o is the permeability of free space with value  \mu_o =  4 \pi * 10^{-7} \ N/A^2

=>      I_b  =  \frac{2 * 3.142  *  0.05 *  4 }{ 2.50  *  4\pi *10^{-7}  * 1000 }

=>      I_b  =  400 \ A

4 0
3 years ago
When an average force F is exerted over a certain distance on a shopping cart of mass m, its kinetic energy increases by 12mv2.
VMariaS [17]

Answer:

A)d=\dfrac{1}{2F}mv^2

B)\Delta KE'=2\times \dfrac{1}{2}mv^2

Explanation:

Given that

Force  = F

Increase in Kinetic energy = \dfrac{1}{2}mv^2

\Delta KE=\dfrac{1}{2}mv^2

we know that

Work done by all the forces =change in the kinetic energy

a)

Lets distance = d

We know work done by force F

W= F .d

F.d=ΔKE

F.d=\dfrac{1}{2}mv^2

d=\dfrac{1}{2F}mv^2

b)

If the force become twice

F' = 2 F

F'.d=ΔKE'

2 F .d = ΔKE'                          ( F.d =Δ KE)

2ΔKE = ΔKE'

\Delta KE'=2\times \dfrac{1}{2}mv^2

Therefore the final kinetic energy will become the twice if the force become twice.

8 0
4 years ago
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