All categories

3 years ago

Another nervous papa bear paces at 1.0 m/s north for 3.0 s, then at 1.6 m/s south for 5.0 s, and then

Physics

1 answer:

lozanna [386]3 years ago

8 0

Answer:

Explanation:

Average speed is total distance traveled over the time needed to do so.

d = vt

v = (1.0(3.0) + 1.6(5.0) + 1.4(4.0) / (3.0 + 5.0 + 4.0)

v = 16.6 / 12

v = 1.383333333...

v = 1.4 m/s

You might be interested in

A box is given a push so that it slides across the floor. How far will it go, given that the coefficient of kinetic friction is

maksim [4K]

D = v^2 / 2ug

d= 3.5^2 / 0,15 x 9.8 m/s^2

the answer should be around 4.2m

hope this helps

8 0

3 years ago

How are electromagnets different from regular magnets?

Digiron [165]

Answer: all of the above

Explanation:

5 0

4 years ago

Fe has the electron configuration [Ar]3d64s2. What is the magnitude of the orbital angular momentum for its most energetic elect

salantis [7]

Answer : The magnitude of the orbital angular momentum for its most energetic electron is, $\sqrt{6}\hbar$

Explanation :

The formula used for orbital angular momentum is:

$L=\sqrt{l(l+1)}\hbar$

where,

L = orbital angular momentum

l = Azimuthal quantum number

As we are given the electronic configuration of Fe is, $[Ar]3d^64s^2$

Its most energetic electron will be for 3d electrons.

The value of azimuthal quantum number(l) of d orbital is, 2

That means, l = 2

Now put all the given values in the above formula, we get:

$L=\sqrt{2(2+1)}\hbar$

$L=\sqrt{6}\hbar$

Therefore, the magnitude of the orbital angular momentum for its most energetic electron is, $\sqrt{6}\hbar$

7 0

3 years ago

A particle of mass m=5.00 kilograms is at rest at t=0.00 seconds. a varying force f(t)=6.00t2−4.00t+3.00 is acting on the partic

Agata [3.3K]

Answer:

43 m/s

Explanation:

Mass, m = 5 kg

Force, F(t) = 6t² - 4t + 3

To find the speed, we first need to get the acceleration, a.

Force is the product of mass and acceleration. It is given as:

F = ma

Therefore, acceleration is:

a(t) = F(t)/m

a(t) = (6t² - 4t + 3) / 5

a(t) = 1.2t² - 0.8t + 0.6

Acceleration is the differentiation of velocity with respect to time, t. Therefore, to get velocity, v, we integrate a(t):

a(t) = dv(t) / dt

=> v(t) = (1.2/3)t³ - (0.8/2)t² + 0.6t

v(t) = 0.4t³ - 0.4t² + 0.6t

Therefore, at time t = 5secs, velocity is:

v(5) = 0.4 * (5³) - 0.4 * (5²) + 0.6 * 5

v(5) = 50 - 10 + 3

v(5) = 43 m/s

The velocity at time, t = 5 secs is 43 m/s

8 0

3 years ago

A boy of mass 50 kg walks up a staircase of 10 steps each 15 cm high. Calculate the work done.

Burka [1]

Answer:

735 J

Explanation:

Total height reached(displaced)=10x15 cm

= 10 x 15/100 m

= 1.5 m

Workdone = F.S (force x displacement)

Here, the boy is traveling against the gravitation force(=mg) , and traveled a height of 1.5m

Hence,

Workdone = 50 x 9.8 x 1.5 J

= 735 J

3 0

3 years ago