Answer:Half the wavelength
Explanation: Destructive Interencce is a type of wave superimposition which involves opposing waves, in this case the Trouph of one wave aligns with the crest of the opposing wave. In this case the smallest distance for the maximum destructive wave to take place is have the wavelength,if the wavelength is one lambda the smallest wavelength for the maximum destructive wave to occur is half the wavelength.
Answer:
Explanation:
GIVEN
Force (F) = 8 N
Distance (d) = 2.5 metres
Work done = ?
WE know we have the formula
work done = F * d
Work done = 8 * 2.5
= 20 Joule
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Answer:
1. T₁ = 500 N
2. T₂ = 866 N
Explanation:
Please see attached photo for the diagram.
Thus, we can obtain obtained the value of T₁ and T₂ as follow:
1. Determination of T₁
Angle θ = 30
Hypothenus = 100 kg
Opposite = T₁ =?
Sine θ = Opposite /Hypothenus
Sine 30 = T₁ / 100
Cross multiply
T₁ = 100 × Sine 30
T₁ = 100 × 0.5
T₁ = 50 Kg
Multiply by 10 to express in Newton
T₁ = 50 × 10
T₁ = 500 N
2. Determination of T₂
Angle θ = 60
Hypothenus = 100 kg
Opposite = T₂ = ?
Sine θ = Opposite /Hypothenus
Sine 60 = T₂ / 100
Cross multiply
T₂ = 100 × Sine 60
T₂ = 100 × 0.8660
T₂ = 86.6 Kg
Multiply by 10 to express in Newton
T₂ = 86.6 × 10
T₂ = 866 N