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2 years ago

Use the claim to answer the question.

2 answers:

6 0

Scientific evidence such as reflection and photoelectric effect has proven the wave-particle model of electromagnetic radiation to be true.

<h3>What is electromagnet radiation?</h3>

Electromagnetic radiation is radiation produced as a result of the interactions of the electric and magnetic fields.

Some forms of electromagnetic radiation include:

radio waves
microwaves
ultraviolet radiation
visible light

Electromagnetic radiation can be described using a wave model or a particle model.

The wave property of electromagnetic radiation include:

diffraction
reflection
refraction

The particle property of electromagnetic radiation include:

photoelectric effect
Compton effect.

Therefore, the wave-particle model of electromagnetic radiation is correct because it can be backed up by experiments and evidence.

Learn more about wave-particle model at: brainly.com/question/20452331

Lady_Fox [76]2 years ago

3 0

Answer:

I just took the identifying Claims Quick check

Explanation:

1. Claim: Electromagnetic radiation can be described by a wave model or a particle model, depending on the situation.

Is this a scientific claim?

Yes, it can be backed up by experiments and evidence.

2. A student states, "The wave model is better than the particle model for electromagnetic radiation because it is easier to understand." Is the student's statement a scientific claim?

No, it isn't because the statement is an opinion.

3. A student wants to make a scientific explanation regarding the wave model of electromagnetic radiation. Which of the following would be part of the scientific explanation?

Claims

4. A student makes this statement before conducting an experiment on electromagnetic radiation: "We expect the laser to diffract when passed through a slit." Which of the following explains why the student's statement is not a claim?

It is a prediction or hypothesis.

5. Which claim do scientists use to describe electromagnetic radiation?

Electromagnetic radiation exhibits properties of both particles and waves.

6. A physician is going to use high-frequency electromagnetic radiation to treat cancer in a patient. Which is a claim about this event?

A wave model is most useful for describing the frequency of the radiation.

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Answer:

Explanation:

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3 years ago

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What does the Q stand for in the enthalpy of fusion equation?

pychu [463]

The Q in the enthalpy of fusion equation stands for heat energy absorbed or released.

<h3>What is enthalpy?</h3>

In thermodynamics, enthalpy is a measure of the heat content of a chemical or physical system.

The enthalpy of fusion is the amount of heat energy required to convert a unit mass of a solid at its melting point into a liquid without an increase in temperature.

Its units are usually Joules per gram (J/g) or calories per gram (cal/g).

The enthalpy of fusion equation is given as follows:

Q = m·ΔHf

Where;

Q = heat energy
m = mass
ΔHf = heat of fusion

Therefore, the Q in the enthalpy of fusion equation stands for heat energy absorbed or released.

Learn more about enthalpy of fusion at: brainly.com/question/20897184

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2 years ago

What is a reasonable measurement for the distance to Neptune?

IRINA_888 [86]

Answer:

30 kilometers is a reasonable measurement

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3 years ago

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Drag each statement to the correct location on the table.

Brut [27]

Answer:

Solid:

- has definite shape and volume.

- change to liquid on heating.

Liquid:

- has definite volume but does not have definite shape .

- changes to solid on cooling.

Gas :

- does not have definite shape or volume.

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8 0

3 years ago

Two obiect accumulated a charge of

tamaranim1 [39]

Answer:

A. 181.24 N

Explanation:

The magnitude of hte electrostatic force between two charged objects is given by the equation

$F=k\frac{q_1 q_2}{r^2}$

where

k is the Coulomb's constant

q1, q2 are the magnitudes of the two charges

r is the separation between the charges

In this problem, we have:

$q_1=4.5\mu C=4.5\cdot 10^{-6}C$ is the magnitude of the 1st charge

$q_2=2.8\mu C=2.8\cdot 10^{-6}C$ is the magnitude of the 2nd charge

r = 2.5 cm = 0.025 m is the separation between the charges

Therefore, the magnitude of the electric force is:

$F=\frac{(9\cdot 10^9)(4.5\cdot 10^{-6})(2.8\cdot 10^{-6})}{(0.025)^2}=181.44 N$

So, the closest answer is

A) 181.24 N

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4 years ago