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balandron [24]
3 years ago
13

If interest compound at 20% per year how long will it take 50000 to accumulate to 86400

Mathematics
1 answer:
yKpoI14uk [10]3 years ago
3 0
3 years. 50000x1.2^3=86400
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Find the dimensions of a rectangle whose area is 208 cm2 and whose perimeter is 58 cm
Mrrafil [7]

Answer:

13cm× 16cm

Step-by-step explanation:

Please see attached picture for full solution.

3 0
3 years ago
I need help pls show work dont just answer for the pts..
Marysya12 [62]

Answer:

volume = 24,501.42

Step-by-step explanation: the way i did it:

first find the radius, 34 divided by 2 = 17π

then multiply the radius by itself 17 x 17 = 289

after, multiply 289 by 27 to get 7,803

then multiply 7803 by 3.14 to get 24,501.42

Hope this is correct!

(p.s.) if you do it on a calculator and use the pi symbol (π) the answer would be 24,513.84

8 0
3 years ago
Equation don't has three time much money than his brother who has 25.
mash [69]
First think out the equation, once you've done that multiply 3 by 25 to get 75
5 0
4 years ago
Which two values of x are roots of the polynomial below?<br> x2 + 5x+7
Dmitry [639]

Answer:

The roots are

x=\frac{-5+i\sqrt{3}}{2}  and  x=\frac{-5-i\sqrt{3}}{2}

Step-by-step explanation:

we have

x^{2} +5x+7

To find the roots equate the polynomial to zero and cmplete the square

x^{2} +5x+7=0

x^{2} +5x=-7

(x^{2} +5x+2.5^{2})=-7+2.5^{2}

(x^{2} +5x+6.25)=-0.75

rewrite as perfect squares

(x+2.5)^{2}=-0.75

take square root both sides

(x+2.5)=(+/-)\sqrt{-\frac{3}{4}}

Remember that

i=\sqrt{-1}

substitute

(x+2.5)=(+/-)i\sqrt{\frac{3}{4}}

(x+\frac{5}{2})=(+/-)i\frac{\sqrt{3}}{2}

x=-\frac{5}{2}(+/-)i\frac{\sqrt{3}}{2}

therefore

The roots are

x=\frac{-5+i\sqrt{3}}{2}

x=\frac{-5-i\sqrt{3}}{2}

4 0
3 years ago
Complete the statement for the equation y=-1/2x-1/2.
skad [1K]

9514 1404 393

Answer:

  -1/2

Step-by-step explanation:

The constant in the equation is the value that y has when x=0, because the x-term evaluates to zero when x=0. The constant term in this equation is -1/2, so that is the y-value when x=0.

  (x, y) = (0, -1/2) . . . . where the graph crosses the y-axis

6 0
3 years ago
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