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RSB [31]
3 years ago
9

(Double points) A mechanic used a wrench 0.6 meters long to loosen rusted lug nuts on a truck wheel. By standing on the end of t

he wrench, he was able to apply his entire 100 kg weight to the wrench. How much torque did he apply?
Physics
1 answer:
Korolek [52]3 years ago
3 0

Answer:

Torque, \tau=588\ N-m

Explanation:

It is given that,

Length of the wrench, l = 0.6 m

Mass of the wrench, m = 100 kg

We know that the torque applied by mechanic is given by :

\tau=Fl

\tau=mgl

\tau=100\times 9.8\times 0.6

\tau=588\ N-m

So, the torque applied by the mechanic is 588 N-m. Hence, this is the required solution.

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Answer:

c

Explanation:

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A difference In density between gases creates buoyancy which is the ability of an object to float. 0°C helium has a density of .
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Answer:

mass = 0.18 [kg]

Explanation:

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density = \frac{mass}{volume} \\\\where:\\volume = 1 [m^3]\\density = 0.18[kg/m^3]

mass = 0.18*1

mass = 0.18 [kg]

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Amelia wanted to measure the mass of an object. Which SI unit should she use? A. kg B. amp C. mL D. K
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3 years ago
Steel wire rope is used to lift a heavy object. We use a 3.1m steel wire that
kaheart [24]

Answer:

Young's modulus for the rope material is 20.8 MPa.    

 

Explanation:

The Young's modulus is given by:

E = \frac{FL_{0}}{A\Delta L}

Where:

F: is the force applied on the wire

L₀: is the initial length of the wire = 3.1 m

A: is the cross-section area of the wire

ΔL: is the change in the length = 0.17 m

The cross-section area of the wire is given by the area of a circle:

A = \pi r^{2} = \pi (\frac{0.006 m}{2})^{2} = 2.83 \cdot 10^{-5} m^{2}

Now we need to find the force applied on the wire. Since the wire is lifting an object, the force is equal to the tension of the wire as follows:

F = T_{w} = W_{o}

Where:

T_{w}: is the tension of the wire

W_{o}: is the weigh of the object = mg

m: is the mass of the object = 1700 kg

g: is the acceleration due to gravity = 9.81 m/s²

F = mg = 1700 kg*9.81 m/s^{2} = 16677 N

Hence, the Young's modulus is:

E = \frac{16677 N*0.006 m}{2.83 \cdot 10^{-5} m^{2}*0.17 m} = 20.8 MPa          

Therefore, Young's modulus for the rope material is 20.8 MPa.                

I hope it helps you!                                    

7 0
3 years ago
What is the purpose of the three R’s of resource management?
svlad2 [7]
The three R's<span> – reduce, reuse and recycle – all help to cut down on the amount of waste we throw away. They conserve natural </span>resources<span>, landfill space and energy.

Hope that helped :)</span>
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4 years ago
Read 2 more answers
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