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RSB [31]
3 years ago
9

(Double points) A mechanic used a wrench 0.6 meters long to loosen rusted lug nuts on a truck wheel. By standing on the end of t

he wrench, he was able to apply his entire 100 kg weight to the wrench. How much torque did he apply?
Physics
1 answer:
Korolek [52]3 years ago
3 0

Answer:

Torque, \tau=588\ N-m

Explanation:

It is given that,

Length of the wrench, l = 0.6 m

Mass of the wrench, m = 100 kg

We know that the torque applied by mechanic is given by :

\tau=Fl

\tau=mgl

\tau=100\times 9.8\times 0.6

\tau=588\ N-m

So, the torque applied by the mechanic is 588 N-m. Hence, this is the required solution.

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taurus [48]
According to Newton laws of motion, 
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Here, m = 1,560 Kg
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Substitute their values, 
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6 0
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An amateur astronomer looks at the moon through a telescope with a 15-cm-diameter objective. What is the minimum separation betw
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Answer:

  y = 128.0 km

Explanation:

The minimum separation of two objects is determined by Rayleygh's diffraction criterion, which establishes that two bodies are solved if the first minino of diffraction of one coincides with the central maximum of the second, with this criterion the diffraction equation remains

                       

the diffraction equation for the first minimum is

                       a sin θ = λ

In the case of circular openings, the equation must be solved in polar coordinates, leaving the expression, we use the approximation that the sine of tea is very small.

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to find the distance we can use trigonometry

             tan θ = y / L

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substituting

              y / L = λ / d

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let's calculate

              y = 384 10⁸ 500 10⁻⁹ / 0.15

              y = 1.28 10⁵ m

Let's reduce to km

             y = 1.28 10⁵ m (1km / 10³ m)

             y = 128.0 km

the correct answer is 120 km away

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