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dexar [7]
3 years ago
14

Two cars approach a street corner at right angles to each

Physics
1 answer:
irakobra [83]3 years ago
4 0

Answer:

the angle is given by

Tan theta = 35/59 = 0.59

so theta = Tan ^-1 ( 0.59 )

theta = 30.54 deg.

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aivan3 [116]
What are you trying to say?
6 0
3 years ago
Un avión tarda en llegar a su destino 12 horas. Si recorrió una distancia de 10.700 kilómetros. Calcular su velocidad y expesarl
elixir [45]

Given that,

Distance, d = 10700 km

Time taken by the airplane to complete the destination, t = 12 hours

We need to find the speed of the airplane. It is equal to the total distance covered divided by total time taken. So,

v=\dfrac{d}{t}\\\\v=\dfrac{10700\ km}{12\ h}\\\\v=891.66\ km/h

We know that,

1 km = 1000 m

1 h = 3600 s

So,

v=891.66\ km/h =\dfrac{891.66\times 1000\ m}{3600\ s}\\\\v=247.68\ m/s

So, the speed of the airplane is 891.66 km/h or 247.68 m/s.

5 0
3 years ago
How long would it take for a sound impulse to travel through an aluminum rod 1,500 meters long?
NNADVOKAT [17]
<span>I believe the answer is 0.29.</span>
5 0
3 years ago
Read 2 more answers
What kind of units as force measured by
Readme [11.4K]

Answer:

Newtons

Explanation:

5 0
3 years ago
Read 2 more answers
In a double-slit experiment, light from two monochromatic light sources passes through the same double slit. The light from the
MatroZZZ [7]

Answer:

The wavelength is \lambda_2 =  534 *10^{-9} \ m

Explanation:

From the question we are told that

   The wavelength of the first light is  \lambda _ 1 =  587 \ nm

    The order of the first light that is being considered is  m_1  =  10

     The order of the second light that is being considered is  m_2  =  11

Generally the distance between the fringes for the first light is mathematically represented as

      y_1 =  \frac{ m_1  * \lambda_1 *  D}{d}

 Here  D is the distance from the screen

 and    d  is the distance of separation of the slit.

      For the second light the distance between the fringes is  mathematically represented as

         y_2 =  \frac{ m_2  * \lambda_2 *  D}{d}

Now given that both of the light are passed through the same double slit

       \frac{y_1}{y_2}  =  \frac{\frac{m_1 *  \lambda_1 * D}{d}  }{\frac{m_2 *  \lambda_2 * D}{d}  } = 1

=>    \frac{ m_1 *  \lambda _1  }{ m_2  *  \lambda_2} =  1

=>     \lambda_2 =  \frac{m_1 *  \lambda_1}{m_2}

=>    \lambda_2 =  \frac{10  *   587 *10^{-9}}{11}

=>   \lambda_2 =  534 *10^{-9} \ m

4 0
3 years ago
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