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LUCKY_DIMON [66]
3 years ago
11

3/4 minus 1/8 in simplest form

Mathematics
1 answer:
mash [69]3 years ago
6 0
.625 or if you want it in a fraction it is 625/1000
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(1 - cosx) (1 + 1/cosx) = sinxtanx
Nataly [62]

Answer:

cos x ≠ 0 ⇔ x ≠ \frac{pi}{2}+k.pi ; k ∈ N

(1-cosx)(1+\frac{1}{cosx})=sinx.tanx\\\\(1-cosx)(\frac{cosx+1}{cosx})=sinx.\frac{sinx}{cosx}\\\\ \frac{1-cos^{2} x}{cosx} =\frac{sin^{2}x }{cosx}\\\\=>1-cos^{2}x=sin^{2}x

<=> cos²x + sin²x = 1

⇔ 1 = 1

=> x =  { R \ (pi/2 + k.pi); k ∈ N}

Step-by-step explanation:

5 0
3 years ago
0.99 divided by 1.1.
NeTakaya

Answer: 0.9

Step-by-step explanation:

6 0
1 year ago
Figure ABCD is transformed to A′B′C′D′, as shown: A coordinate plane is shown. Figure ABCD has vertices A at 3 comma 1, B at 3 c
Marta_Voda [28]
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7 0
3 years ago
Can someone help me plz
koban [17]

inaccurate

3 less than would be x-3, but 3-x would be 3 more

6 0
3 years ago
Military radar and missile detection systems are designed to warn a country of enemy attacks. A reliability question deals with
Nadusha1986 [10]

Answer:

Step-by-step explanation:

Given that a particular detection system has a 0.83 probability of detecting a missile attack.

Also each system is independent of the other to detect missile attack.

a)  the probability that a single detection system will detect an attack=0.83

b) the probability that at least one of the systems will detect the attack given two systems= 1-Prob no system detects

=1-(1-0.83)(1-0.83)\\\\=1-0.0289\\=0.9711

c)  If three systems are installed,  the probability that at least one of the systems  will detect the attack

= 1- none of the three systems detect attack

= (1-0.17^3)\\=1-0.004913\\=0.995087

d) We find that probability of detecting is more if we increase the system form 1 to 2 and 2 to 3.

Hence for safety and defence purpose multiple detection system is recommended.

7 0
3 years ago
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