Question

0.556 g of a solid white acid are dissolved in water and completely neutralized by the addition of 52.38 mL of 0.396 M NaOH. Calculate the molar mass of the acid, assuming it to be a monoprotic acid

Answer 1

Answer:

$M_{acid}=26.804g/mol$

Explanation:

Hello,

In this case, by knowing that the used NaOH equals in moles the acid (monoprotic) as shown below, during the titration:

$n_{acid}=n_{NaOH}$

By knowing the volume and the concentration of the NaOH, one obtains:

$n_{acid}=0.05238L*0.396\frac{mol}{L}=0.0207mol$

Thus, the molar mass of the acid is computed based on the previously computed moles and the given mass as follows:

$M_{acid}=\frac{m_{acid}}{n_{acid}}=\frac{0.556g}{0.0207mol}=26.804g/mol$

Best regards.