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3 years ago

Avogradro's number is the number of particles in one gram of carbon- 12 atom true or false?

Chemistry

1 answer:

LiRa [457]3 years ago

5 0

Answer:

True

Explanation:

The value of the mole is equal to the number of atoms in exactly 12 grams of pure carbon-12. 12.00 g C-12 = 1 mol C-12 atoms = 6.022 × 1023 atoms • The number of particles in 1 mole is called Avogadro's Number (6.0221421 x 1023).

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How many moles are there in 8.50 X 1024 molecules of sodium sulfate, Na2SO3?

il63 [147K]

Answer:

<h2>14.12 moles</h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

$n = \frac{N}{L} \\$

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

$n = \frac{8.50 \times {10}^{24} }{6.02 \times {10}^{23} } \\ = 14.119601...$

We have the final answer as

<h3>14.12 moles</h3>

Hope this helps you

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3 years ago

Which subatomic particle do you think is most important to an atom’s identity?

Sonja [21]

The subatomic particle that identifies the atom is the number of protons. This is what distinguishes an element that is is flammmable, hydrogen to one that is essential component in water, oxygen.

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3 years ago

1. Drug dependence from drug abuse

tia_tia [17]

Answer:

✅

Explanation:

DON'T USE DRUGS BECAUSE IT IS GOING DEATH

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3 years ago

The following reaction produces ethanoic acid (CHACOOH) from methanol (CH3OH) and carbon

tigry1 [53]

Answer:

$\boxed{\text{300 g}}$

Explanation:

We will need a balanced chemical equation with masses and molar masses, so, let's gather all the information in one place.

M_r: 32 60

CH₃OH + CO ⟶ CH₃COOH

m/g: 160

(a) Moles of CH₃OH

$\text{Moles of CH$_{3}$OH} = \text{160 g CH$_{3}$OH }\times \dfrac{\text{1 mol CH$_{3}$OH }}{\text{32 g CH$_{3}$OH}}= \text{5.00 mol CH$_{3}$OH}$

(b) Moles of CH₃COOH

$\text{Moles of CH$_{3}$COOH} = \text{5.00 mol CH$_{3}$OH } \times \dfrac{\text{1 mol CH$_{3}$COOH}}{\text{1 mol CH$_{3}$OH }} = \text{5.00 mol CH$_{3}$COOH}$

(c) Mass of CH₃COOH

$\text{Mass of CH$_{3}$COOH} =\text{5.00 mol CH$_{3}$COOH} \times \dfrac{\text{60 g CH$_{3}$COOH}}{\text{1 mol CH$_{3}$COOH}} = \textbf{300 g CH$_{3}$COOH}\\\\\text{The maximum mass of ethanoic acid that can be produced is $\boxed{\textbf{300 g}}$}$

3 0

3 years ago

How many liters of volume is one mole of gas at standard temperature and<br> pressure?

horsena [70]

22.7 liters

The molar volume of an ideal gas depends on the temperature and pressure. One mole of any ideal gas occupies 22.7 liters at 0 0C and 1 bar (STP).

Hope this helped

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3 years ago

Avogradro's number is the number of particles in one gram of carbon- 12 atom true or false?​

Avogradro's number is the number of particles in one gram of carbon- 12 atom true or false?