___an expression that is a sum or difference of three terms

Carlito scored a 92 on his first math test, a 94 on the second, and an 88 on the third. If each test is worth points and there a

grigory [225]

Let x be his score on the last test so that to get an average of 90
His to average score at year end (4 terms), including the last is:
(92 +94 + 98 + x)/4 =90
(92 +94 + 98 + x) =4 x 90
x = - 274 + 360
x= 86

3 0

4 years ago

What strategies do you use when multiplying decimals? Share your thinking using 2-3 sentences. This is an open-ended question so

Anit [1.1K]

I’m not sure if this is actually a strategy but can I get brainliest please. If I’m not allowed to use a calculator then I would covert the decimals to fractions. I would covert them to the simplest fractions before multiplying so that the answer is as closest to its simplest form as possible.

8 0

2 years ago

Does anybody know this if so can you help me explain and do it for brainlist ..

mr_godi [17]

Question 1: m = 2 - 10 / 1 - 8 = -8 / -7

3 0

3 years ago

Read 2 more answers

Evaluate the surface integral S F · dS for the given vector field F and the oriented surface S. In other words, find the flux of

Law Incorporation [45]

Answer:

Step-by-step explanation:

To solve this problem, we will use the following two theorems/definitions:

- Given a vector field F of the form (P(x,y,z),Q(x,y,z),W(x,y,z)) then the divergence of F denoted by $\nabla \cdot F = \frac{\partial P}{\partial x}+\frac{\partial Q}{\partial y}}+\frac{\partial W}{\partial z}$

- (Gauss' theorem)Given a closed surface S, the following applies

$\int_{S} F\cdot \vec{n} dS = \int_{V} \nabla \cdot F dV$

where n is the normal vector pointing outward of the surface and V is the volume bounded by the surface S.

Let us, in our case, calculate the divergence of the given field. We have that

$\nabla \cdot F = \frac{\partial}{\partial x}(x)+\frac{\partial}{\partial y}(2y)+ \frac{\partial}{\partial z}(5z) = 1+2+5 = 8$

Hence, by the Gauss theorem we have that

$\int_{S} F\cdot \vec{n} dS = \int_{V} 8 dV = 8\cdot\text{Volume of V}$

So, we must calculate the volume V bounded by the cube S.

We know that the vertices are located on the given points. We must determine the lenght of the side of the cube. To do so, we will take two vertices that are on the some side and whose coordinates differ in only one coordinate. Then, we will calculate the distance between the vertices and that is the lenght of the side.

Take the vertices (1,1,1) and (1,1-1). The distance between them is given by

$\sqrt[]{(1-1)^2+(1-1)^2+(1-(-1)^2} = \sqrt[]{4} = 2$ .

Hence, the volume of V is $2\cdot 2 \cdot 2 = 8$ . Then, the final answer is

$\int_{S} F\cdot \vec{n} dS =8\cdot 8 = 64$

5 0

3 years ago

The scores of eight grade students in a math test are normally distributed with a mean of 57.5 and a standard deviation of 6.5.

rewona [7]

Work out the z scores for 51 and 54
z1 = (51 - 57.5) / 6.5 = -1
z2 = (64 - 57.5)/6.5 = 1
from tables of normal distribution this value os 3413 + 3413 = 68.26%

so the answer is c

8 0

4 years ago