All categories

2 years ago

Drag steps of the solution into order to solve for x in the equation 8(x+7)=104

2 answers:

Nadusha1986 [10]2 years ago

6 0

Hello!

The first step to solving this equation would be to distribute the 8 to x+7 to simplify the equation:
(8*x)+(8*7)=104
8x+56=104

The second step would be to then subtract 56 from both sides to isolate 8x:
8x+56-56=104-56
8x=48

Finally, the last step would be to divide both sides by 8 to solve for x:
8x/8=48/8
x=6

Your final answer would be x=6

Hope this helps, and Happy New Year!

strojnjashka [21]2 years ago

4 0

8x + 56 = 104
8x = 48
x = 6

You might be interested in

No one has answered my past 5 questions so I would be really greatful if you could help out.

vlabodo [156]

Answer:

$x^{4}-x^{3}-2x^{2}-4x+12$

Step-by-step explanation:

(f-g)(x) just means f(x) - g(x)

In order to make it easier, multiple g(x) by -1 and add.

Thus, it equals $x^{4}-x^{3}-2x^{2}-4x+12$

3 0

3 years ago

Read 2 more answers

Jingle Corporation produces toy footballs. Each football sells for $9.95 with a variable unit cost of $7.10. Assuming a fixed co

____ [38]

Each football is sold for $9.95. To make one of these football costs $7.10.
There is a profit of $2.85. Divide 11,400 by 2.85 to see how many footballs would have to sell to break even.

11,400 / 2.85 = 4000.

4000 footballs would have to be sold to break even.

5 0

3 years ago

A random draw is being designed for 210 participants. A single winner is to be chosen, and all the participants must have an equ

Over [174]

Answer: The correct number of balls is (b) 4.

Step-by-step explanation: Given that a single winner is to be chosen in a random draw designed for 210 participants. Also, there is an equal probability of winning for each participant.

We are using 10 balls, numbered through 0 to 9. We are to find the number of balls which needs to be picked up, regardless of order, so that each of the 210 participants can be assigned a unique set of numbers.

Let 'r' represents the number of balls to be picked up.

Since we are choosing from 10 balls, so we must have

$^{10}C_r=210.$

The value of 'r' can be any one of 0, 1, 2, . . , 10.

Now,

if r = 1, then

$^{10}C_1=\dfrac{10!}{1!(10-1)!}=\dfrac{10!}{1!9!}=\dfrac{10\times 9!}{1\times 9!}=10$

If r = 2, then

$^{10}C_2=\dfrac{10!}{2!(10-2)!}=\dfrac{10!}{2!8!}=\dfrac{10\times 9\times 8!}{2\times 1\times 8!}=45$

If r = 3, then

$^{10}C_3=\dfrac{10!}{3!(10-3)!}=\dfrac{10!}{3!7!}=\dfrac{10\times 9\times 8\times 7!}{3\times 2\times 1\times 7!}=120$

If r = 4, then

$^{10}C_4=\dfrac{10!}{4!(10-4)!}=\dfrac{10!}{4!6!}=\dfrac{10\times 9\times 8\times\times 7\times 6!}{4\times 3\times 2\times 1\times 6!}=210.$

Therefore, we need to pick 4 balls so that each participant can be assigned a unique set of numbers.

Thus, (b) is the correct option.

4 0

3 years ago

Read 2 more answers

Determine the number of elements in the Sample Space for each of the following:

lesantik [10]

Sample space is the set of possible outcomes of an experiment.
1. Tossing a coin three times
There are possible outcomes.
Tossing the coin for the first time it can be a haid (H) or a tail (T). So, we can have this outcomes:
HHH
HHT
HTH
THH
TTH
THT
TTT
total: 6 outcomes
2. The order that the top 5 students will receive their diplomas.
Here we need to find the number of permutations: 5!=5*4*3*2*1=120
3. Tossing a pair of dice
The possible outcomes are the following: (a,b), where a is the first dice and b is the second dice
(1,1)(1,2)(1,3)(1,4)(1,5)(1,6)(2,1)(2,2)(2,3)(2,4)(2,5)(2,6)(3,1)(3,2)(3,3)(3,4)(3,5)(3,6)(4,1)(4,2)(4,3)(4,4)(4,5)(4,6)(5,1)(5,2)(5,3)(5,4)(5,5)(5,6)(6,1)(6,2)(6,3)(6,4)(6,5)(6,6) , total 36 possible outcomes.

5 0

3 years ago

Can someone tell me the answer for 7.05 x 9.4

scoundrel [369]

66.27 is the answer

3 0

3 years ago

Read 2 more answers