You need to find the circumference of the whole circular pool and then subtract from it the arc length that is 1/4 of the circumference. The circumference formula is C = (3.14)(d), which in our case is 3.14(40) which is 125.6. Now we need the arc length we need to take away. 1/4 of a circle corresponds to a 90 degree angle, so in the formula for arc length, we have this:

which equals 31.4. Now subtract that from the circumference of the whole circle and you get the outside of the circle minus that arc length. That's 94.2. But we have to go in the radius times 2 to enclose the pie shaped piece we cut away. So we have 134.2. She should've just stuck with enclosing the circle; she would have used less fencing!
It would be less because when you multiply something by 1/2 you are basically dividing it by 2, finding half. So when you multiply 9 8/9 by 1/2 your product would be less than 9 8/9
Answer:
9(p + 4)
Step-by-step explanation:
One of the unknown variable is p.
First of all, we know that the number is 9 times as big (multiplication) as the new number obtained through the addition of four to p i.e (p + 4).
Translating the word problem into an algebraic expression, we have;
9 * (p + 4) = 9(p + 4)
Simplifying further, we have;
9p + 36
Answer:
chisquare = 31.667
degree of freedom = 2
Step-by-step explanation:
Formula for chisquare test = (O-E)²/E
total number observations= 60 + 25 + 15 = 100
Estimated E,
80% x 100 = 80
15%x100 = 15
5% x 100 = 5
chisquare =

= 5 + 6.67 + 20
= 31.667
from the calculation above the value of the chisquare statistic = 31.67
the degree of freedom is the number of samples in the test n - 1
= 3-1
= 2
I have solve this question also in a tabular form to aid understanding in the file i uploaded.
thank you and good luck!